On determinants involving $(\frac{j+k}p)\pm(\frac{j-k}p)$

Deyi Chen, Zhi-Wei Sun
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Abstract

Let $p=2n+1$ be an odd prime. In this paper, we mainly evaluate determinants involving $(\frac {j+k}p)\pm(\frac{j-k}p)$, where $(\frac{\cdot}p)$ denotes the Legendre symbol. When $p\equiv1\pmod4$, we determine the characteristic polynomials of the matrices $$\left[\left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)\right]_{1\le j,k\le n}\ \ \text{and}\ \ \left[\left(\frac{j+k}p\right)-\left(\frac{j-k}p\right)\right]_{1\le j,k\le n},$$ and also prove that \begin{align*} &\ \left|x+\left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)+\left(\frac jp\right)y+\left(\frac kp\right)z+\left(\frac{jk}p\right)w\right|_{1\le j,k\le n} \\=&\ (-p)^{(p-5)/4}\left(\left(\frac{p-1}2\right)^2wx-\left(\frac{p-1}2y-1\right)\left(\frac{p-1}2z-1\right)\right), \end{align*} which was previously conjectured by the second author.
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关于涉及 $(\frac{j+k}p)\pm(\frac{j-k}p)$ 的行列式
假设 $p=2n+1$ 是奇素数。本文主要评估涉及 $(\frac {j+k}p)\pm(\frac{j-k}p)$ 的行列式,其中 $(\frac\{cdot}p)$ 表示列根德符号。当 $p\equiv1\pmod4$ 时,我们确定矩阵$$left[\left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)\right]_{1/le j、k\len}\text{and}\left[\left(\frac{j+k}p\right)-\left(\frac{j-k}p\right)\right]_{1\le j、klen},$$并且还证明:begin{align*} &\left|x+left(\frac{j+k}p\right)+\left(\frac{j-k}p\right)+left(\fracjp\right)y+left(\frac kp\right)z+left(\frac{jk}p\right)w\right|_{1\le j,k\len}\=&\(-p)^{(p-5)/4}\left(\left(\frac{p-1}2\right)^2wx-\left(\frac{p-1}2y-1\right)\left(\frac{p-1}2z-1\right)\right),\end{align*} 这是第二位作者之前的猜想。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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