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引用次数: 8

摘要

在PODS'17中,Ketsman和Suciu给出了MPC模型中的一种算法,用于计算任何自然连接的结果,其中每个输入关系都有两个属性。实现最优负载O(m/p^{1/ρ}) -其中m是输入关系的总大小,p是机器的数量,ρ是连接的分数边覆盖数-他们的算法需要7轮才能完成。本文提出了一种更简单的算法,保证3轮的负载相同(实际上,第二轮只产生O(p²)的负载来传输某些统计数据,以协助最后一轮的机器分配)。我们的算法是由一个新定理实现的,该定理为问题的结构提供了新的见解,并使我们更接近于理解二进制关系上的连接可以用负载O(m/p^{1/ρ})来解决的内在原因。
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A Simple Parallel Algorithm for Natural Joins on Binary Relations
In PODS'17, Ketsman and Suciu gave an algorithm in the MPC model for computing the result of any natural join where every input relation has two attributes. Achieving an optimal load O(m/p^{1/ρ}) - where m is the total size of the input relations, p the number of machines, and ρ the fractional edge covering number of the join - their algorithm requires 7 rounds to finish. This paper presents a simpler algorithm that ensures the same load with 3 rounds (in fact, the second round incurs only a load of O(p²) to transmit certain statistics to assist machine allocation in the last round). Our algorithm is made possible by a new theorem that provides fresh insight on the structure of the problem, and brings us closer to understanding the intrinsic reason why joins on binary relations can be settled with load O(m/p^{1/ρ}).
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