统计广义Nörlund-Euler可和性方法的一个Tauberian定理

Pub Date : 2019-12-01 DOI:10.2478/ausm-2019-0019
N. Braha
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引用次数: 0

摘要

摘要设(pn)和(qn)为任意两个非负实数序列,其中Rn:=∑k=0npkqn-k≠0 (n∈𝕅)_:= {{\rm{R}}{\rm{n}}}\sum\limits _ =0 ^ __ - {{\rm{k}}}{\rm{n}}{{{\rm{p}}{\rm{k}}}{{\rm{q}}{{\rm{n}}{\rm{k}}}}}\ne 0\,\,\,\, \left ({{\rm{n}}\in{\rm\mathbb{N}}}\right)用En1 _^1−表示欧拉可和性方法。设(xn)是实数或复数的序列,集合Np,qnEn1:=1Rn∑k=0npkqn-k12k∑v=0k(vk)xv _,^_^1: =1 {\rm{E}}{\rm{n}}{\rm{N}}{{\rm{p}}{\rm{q}}}{\rm{n}}{\rm{E}}{\rm{n}}{\over _ {{{\rm{R}}{\rm{n}}}}}\sum\limits _ =0 ^ __1 {{\rm{k}}}{\rm{n}}{{{\rm{p}}{\rm{k}}}{{\rm{q}}{{\rm{n - k}}}}{\over 2^ {{{\rm{k}}}}}\sum\limits _ =0 ^ {{\rm{v}}}{\rm{k}}{\left (_^ {{\rm{v}}{\rm{k}}}\right)_对于n∈n。本文给出了由(xn)的st- np、qnE n1 _、q^_^1 -极限的存在性推导出(xn)的st-极限存在的充分必要条件。如果(xn)是实数序列或复数序列,则这些条件分别是单侧或双面的。{{\rm{x}}{\rm{v}}}}}{\rm{st - N}}{{\rm{p}}}{\rm{n}}{\rm{E}}{\rm{n}}
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A Tauberian theorem for the statistical generalized Nörlund-Euler summability method
Abstract Let (pn) and (qn) be any two non-negative real sequences with Rn:=∑k=0npkqn-k≠0    (n∈𝕅) {{\rm{R}}_{\rm{n}}}: = \sum\limits_{{\rm{k}} = 0}^{\rm{n}} {{{\rm{p}}_{\rm{k}}}{{\rm{q}}_{{\rm{n}} - {\rm{k}}}}} \ne 0\,\,\,\,\left( {{\rm{n}} \in {\rm\mathbb{N}}} \right) With En1 {\rm{E}}_{\rm{n}}^1 − we will denote the Euler summability method. Let (xn) be a sequence of real or complex numbers and set Np,qnEn1:=1Rn∑k=0npkqn-k12k∑v=0k(vk)xv {\rm{N}}_{{\rm{p}},{\rm{q}}}^{\rm{n}}{\rm{E}}_{\rm{n}}^1: = {1 \over {{{\rm{R}}_{\rm{n}}}}}\sum\limits_{{\rm{k}} = 0}^{\rm{n}} {{{\rm{p}}_{\rm{k}}}{{\rm{q}}_{{\rm{n - k}}}}{1 \over {{2^{\rm{k}}}}}\sum\limits_{{\rm{v}} = 0}^{\rm{k}} {\left( {_{\rm{v}}^{\rm{k}}} \right){{\rm{x}}_{\rm{v}}}} } for n ∈ ℕ. In this paper, we present necessary and sufficient conditions under which the existence of the st− limit of (xn) follows from that of st-Np,qnE n1 {\rm{st - N}}_{{\rm{p}},q}^{\rm{n}}{\rm{E}}_{\rm{n}}^1 − limit of (xn). These conditions are one-sided or two-sided if (xn) is a sequence of real or complex numbers, respectively.
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