{"title":"The Omega Rule is $\\mathbf{\\Pi_{1}^{1}}$-Complete in the $\\lambda\\beta$-Calculus","authors":"B. Intrigila, R. Statman","doi":"10.2168/LMCS-5(2:6)2009","DOIUrl":null,"url":null,"abstract":"In a functional calculus, the so called \\Omega-rule states that if two terms P and Q applied to any closed term N return the same value (i.e. PN = QN), then they are equal (i.e. P = Q holds). As it is well known, in the \\lambda\\beta-calculus the \\Omega-rule does not hold, even when the \\eta-rule (weak extensionality) is added to the calculus. A long-standing problem of H. Barendregt (1975) concerns the determination of the logical power of the \\Omega-rule when added to the \\lambda\\beta-calculus. In this paper we solve the problem, by showing that the resulting theory is \\Pi\\_{1}^{1}-complete.","PeriodicalId":148456,"journal":{"name":"arXiv: Logic in Computer Science","volume":"50 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2009-03-07","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"4","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv: Logic in Computer Science","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.2168/LMCS-5(2:6)2009","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 4
Abstract
In a functional calculus, the so called \Omega-rule states that if two terms P and Q applied to any closed term N return the same value (i.e. PN = QN), then they are equal (i.e. P = Q holds). As it is well known, in the \lambda\beta-calculus the \Omega-rule does not hold, even when the \eta-rule (weak extensionality) is added to the calculus. A long-standing problem of H. Barendregt (1975) concerns the determination of the logical power of the \Omega-rule when added to the \lambda\beta-calculus. In this paper we solve the problem, by showing that the resulting theory is \Pi\_{1}^{1}-complete.