Settling the Complexity of Computing Approximate Two-Player Nash Equilibria

A. Rubinstein
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引用次数: 123

Abstract

We prove that there exists a constant ε > 0 such that, assuming the Exponential Time Hypothesis for PPAD, computing an ε-approximate Nash equilibrium in a two-player (n × n) game requires quasi-polynomial time, nlog1-o(1) n. This matches (up to the o(1) term) the algorithm of Lipton, Markakis, and Mehta [54]. Our proof relies on a variety of techniques from the study of probabilistically checkable proofs (PCP), this is the first time that such ideas are used for a reduction between problems inside PPAD. En route, we also prove new hardness results for computing Nash equilibria in games with many players. In particular, we show that computing an ε-approximate Nash equilibrium in a game with n players requires 2Ω(n) oracle queries to the payoff tensors. This resolves an open problem posed by Hart and Nisan [43], Babichenko [13], and Chen et al. [28]. In fact, our results for n-player games are stronger: they hold with respect to the (ε,δ)-WeakNash relaxation recently introduced by Babichenko et al. [15].
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求解近似二人纳什均衡的复杂度
我们证明了存在一个ε > 0的常数,使得在PPAD的指数时间假设下,计算两人(n × n)博弈中的ε-近似纳什均衡需要拟多项式时间nlog1-o(1) n。这与Lipton, Markakis和Mehta的算法(直到o(1)项)相匹配[54]。我们的证明依赖于概率可检验证明(PCP)研究中的各种技术,这是第一次将这些思想用于PPAD内部问题之间的约简。在此过程中,我们还证明了在有许多参与者的博弈中计算纳什均衡的新硬度结果。特别地,我们证明了在有n个参与者的博弈中计算ε-近似纳什均衡需要2Ω(n)对支付张量的oracle查询。这解决了Hart和Nisan[43]、Babichenko[13]和Chen等[28]提出的一个开放性问题。事实上,我们对n人博弈的结果更强:它们符合Babichenko等人最近引入的(ε,δ)-WeakNash松弛[15]。
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