The invariant Nash equilibrium for stochastic games in multiple access channel

P. Narayanan, L. N. Theagarajan
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引用次数: 2

Abstract

In this paper, we present an iterative best-response algorithm to compute the Nash equilibrium of a power allocation game in a multiple access channel (MAC), where each user greedily chooses a power allocation policy to maximize their average transmission rate. We consider a MAC where the fading channel gains are assumed to be stationary and ergodic processes, taking values from a finite set. The receiver decodes the message of a user by assuming the messages of the rest of the users as noise. The Shannon capacity of a user is considered to be the achievable rate of that user. A user transmits with a transmit power chosen from a finite set of power values, in a selfish manner, such that their average rate of transmission is maximized. We show that the Nash equilibrium of this game is unique, provided the number of users in the system is sufficiently large, but finite. Under this condition, we also show that the equilibrium policy does not change with more number of users coming into the system. We propose a simple greedy algorithm to compute the Nash equilibrium when the number of users is sufficiently large, but finite. The proposed algorithm does not depend upon the parameters of other users and hence, can be computed without any feedback or side-information from other users. We also present numerical results to illustrate the performance of the proposed algorithm.
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多址信道随机对策的不变纳什均衡
本文提出了一种迭代的最佳响应算法来计算多址信道(MAC)中功率分配博弈的纳什均衡,其中每个用户都贪婪地选择功率分配策略以最大化其平均传输速率。我们考虑一个MAC,其中衰落信道增益被假设为平稳和遍历过程,从有限集合中取值。接收端通过将其他用户的信息假设为噪声来解码用户的信息。用户的香农容量被认为是该用户的可实现速率。用户以一种自私的方式从一组有限的功率值中选择发射功率,以使其平均传输速率最大化。我们证明了当系统中的用户数量足够大但有限时,该博弈的纳什均衡是唯一的。在此条件下,均衡策略不随用户数量的增加而变化。我们提出了一个简单的贪婪算法来计算用户数量足够大但有限时的纳什均衡。该算法不依赖于其他用户的参数,因此可以在没有其他用户反馈或侧信息的情况下进行计算。我们还给出了数值结果来说明所提出算法的性能。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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