Correction: Linearity of Unbiased Linear Model Estimators

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Abstract

The author presented a proof that a regression estimator unbiased for all distributions in a sufficiently broad family F0 must be linear. The family was taken to consist of the convolutions of all two-point distributions with a scale-family of smooth densities tending to a point mass at zero. The basic calculations were based solely on the discrete distributions, but the convolutions were introduced so that the family would be a subset of some standard, smooth nonparametric families. For example, adaptive estimation requires enough smoothness so that the Cramér-Rao bound provides optimal asymptotics. Some further comments appear in the supplemental material. The proof required that convergence of the smooth densities to zero implied that the expectations under the smooth convolutions converged to the expectation under the two-point distribution. This requires that the estimate be continuous, and there was a major error in the proof that unbiasedness implies continuity. It appears that continuity cannot be proved using unbiasedness over F0 , but it can be proved using unbiasedness over families of discrete distributions (see supplemental material). Thus, either the estimator must be assumed to be continuous, or a result using only discrete distributions is required. In trying to correct the error, a much simpler proof of the linearity result was found. This proof takes F0 to consist only of discrete distributions. The details are also presented in the supplemental material, but the basic idea is relatively simple: Consider a simplex with center at zero. Each point in the simplex (say −y ) is a convex combination of the vertices of the simplex; that is, −y is the expectation for a (discrete) distribution putting probability pi on vertex zi . Thus, the distribution putting probability 2 on y and 1 2 pi on zi has mean zero. Therefore, by unbiasedness, T(y) is a convex combination of the {T(zi)} ; that is, T(y) is the matrix whose columns are T(zi) times a vector, p , of probabilities. By basic properties of a simplex, p is an affine function of −y ; and so T(y) is an affine function of y . By unbiasedness under a point mass at zero, T(0) = 0 ; and so the affine constant is zero and T must be linear.
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修正:无偏线性模型估计器的线性
证明了对足够宽的族F0中所有分布无偏的回归估计量必须是线性的。这个族被认为是由所有两点分布的卷积组成的,平滑密度的尺度族趋向于一个点的质量为零。基本的计算完全基于离散分布,但是引入了卷积,使得这个族成为一些标准的,光滑的非参数族的子集。例如,自适应估计需要足够的平滑性,以便cram r- rao界提供最优渐近性。补充材料中出现了一些进一步的评论。证明要求平滑密度收敛于零意味着平滑卷积下的期望收敛于两点分布下的期望。这要求估计是连续的,在证明无偏性意味着连续性时存在一个重大错误。看来连续性不能用F0上的无偏性来证明,但可以用离散分布族上的无偏性来证明(见补充材料)。因此,要么必须假设估计量是连续的,要么只需要使用离散分布的结果。在试图纠正错误的过程中,发现了线性结果的一个简单得多的证明。这个证明需要F0只由离散分布组成。细节也在补充材料中提供,但基本思想相对简单:考虑一个中心为零的单纯形。单纯形中的每个点(例如- y)是单纯形顶点的凸组合;也就是说,- y是一个(离散)分布的期望,概率是PI在顶点zi上。因此,y上概率为2,zi上概率为12的分布均值为0。因此,根据无偏性,T(y)是{T(zi)}的凸组合;也就是说,T(y)是一个矩阵,它的列是T(zi)乘以一个概率向量p。根据单纯形的基本性质,p是- y的仿射函数;所以T(y)是y的仿射函数。通过零点质量下的无偏性,T(0) = 0;所以仿射常数为零,T一定是线性的。
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