Throughput-delay scaling in wireless networks with constant-size packets

A. Gamal, J. Mammen, B. Prabhakar, D. Shah
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引用次数: 13

Abstract

In previous work (2004), we characterized the optimal throughput-delay trade-off in static wireless networks as D(n) = Theta(nT(n)), where D(n) and T(n) are the average packet delay and throughput in a network of n nodes, respectively. While this trade-off captured the essential network dynamics, packets needed to scale down with the network size. In this "fluid model", no buffers were required. Due to this packet scaling, D(n) did not correspond to the average delay per bit. That led to the question whether the trade-off remains the same when the packet size is kept constant, which necessitates buffers and packet scheduling in the network. In this paper, we answer this question in the affirmative by showing that the optimal throughput-delay trade-off is still D(n) = Theta(nT(n)), where now D(n) is the average delay per bit. Packets of constant size necessitate the use of buffers in the network, which in turn requires scheduling packet transmissions in a discrete-time queueing network and analyzing the corresponding delay. Our method consists of deriving packet schedules in the discrete-time network by looking at a corresponding continuous-time network and then analyzing the delay induced in the actual discrete network using results from queueing theory for continuous-time networks
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具有固定大小数据包的无线网络中的吞吐量延迟缩放
在之前的工作(2004)中,我们将静态无线网络中最优吞吐量-延迟权衡描述为D(n) = Theta(nT(n)),其中D(n)和T(n)分别是n个节点网络中的平均数据包延迟和吞吐量。虽然这种权衡捕获了基本的网络动态,但数据包需要随着网络大小而缩小。在这个“流体模型”中,不需要缓冲。由于这种分组缩放,D(n)不对应于每比特的平均延迟。这就产生了一个问题,当数据包大小保持不变时,权衡是否保持不变,这就需要在网络中使用缓冲区和数据包调度。在本文中,我们通过证明最优吞吐量-延迟权衡仍然是D(n) = Theta(nT(n))来肯定地回答这个问题,其中现在D(n)是每比特的平均延迟。恒定大小的数据包需要在网络中使用缓冲区,这反过来又需要在离散时间排队网络中调度数据包传输并分析相应的延迟。我们的方法是通过观察相应的连续网络来推导离散网络中的数据包调度,然后利用连续网络排队理论的结果分析实际离散网络中引起的延迟
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