{"title":"Some notes about power residues modulo prime","authors":"D. Mej'ia, Y. Kiriu","doi":"10.18273/revint.v40n1-2022001","DOIUrl":null,"url":null,"abstract":"Let q be a prime. We classify the odd primes p ≠ q such that the equation x2 ≡ q (mod p) has a solution, concretely, we find a subgroup L4q of the multiplicative group U4q of integers relatively prime with 4q (modulo 4q) such that x2 ≡ q (mod p) has a solution iff p ≡ c (mod 4q) for some c ∈ L4q. Moreover, L4q is the only subgroup of U4q of half order containing −1. Considering the ring Z[√2], for any odd prime p it is known that the equation x2 ≡ 2 (mod p) has a solution iff the equation x2 −2y2 = p has a solution in the integers. We ask whether this can be extended in the context of Z[n√2] with n ≥2, namely: for any prime p ≡ 1 (mod n), is it true that xn ≡ 2 (mod p) has a solution iff the equation D2n(x0, . . . , xn−1) = p has a solution in the integers? Here D2n(x̄) represents the norm of the field extension Q(n√2) of Q. We solve some weak versions of this problem, where equality with p is replaced by 0 (mod p) (divisible by p), and the “norm\" Drn(x̄) is considered for any r ∈ Z in the place of 2.","PeriodicalId":402331,"journal":{"name":"Revista Integración","volume":"39 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2022-01-08","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Revista Integración","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.18273/revint.v40n1-2022001","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
Let q be a prime. We classify the odd primes p ≠ q such that the equation x2 ≡ q (mod p) has a solution, concretely, we find a subgroup L4q of the multiplicative group U4q of integers relatively prime with 4q (modulo 4q) such that x2 ≡ q (mod p) has a solution iff p ≡ c (mod 4q) for some c ∈ L4q. Moreover, L4q is the only subgroup of U4q of half order containing −1. Considering the ring Z[√2], for any odd prime p it is known that the equation x2 ≡ 2 (mod p) has a solution iff the equation x2 −2y2 = p has a solution in the integers. We ask whether this can be extended in the context of Z[n√2] with n ≥2, namely: for any prime p ≡ 1 (mod n), is it true that xn ≡ 2 (mod p) has a solution iff the equation D2n(x0, . . . , xn−1) = p has a solution in the integers? Here D2n(x̄) represents the norm of the field extension Q(n√2) of Q. We solve some weak versions of this problem, where equality with p is replaced by 0 (mod p) (divisible by p), and the “norm" Drn(x̄) is considered for any r ∈ Z in the place of 2.