A result related to the Sendov conjecture

IF 0.7 4区 数学 Q2 MATHEMATICS Annales Polonici Mathematici Pub Date : 2023-01-01 DOI:10.4064/ap221118-1-6
Robert Dalmasso
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引用次数: 0

Abstract

The Sendov conjecture asserts that if $p(z) = \prod_{j=1}^{N}(z-z_j)$ is a polynomial with zeros $|z_j| \leq 1$, then each disk $|z-z_j| \leq 1$ contains a zero of $p'$. Our purpose is the following: Given a zero $z_j$ of order $n \geq 2$, determine whether there exists $\zeta \not= z_j$ such that $p'(\zeta) = 0$ and $|z_j - \zeta| \leq 1$. In this paper we present some partial results on the problem.
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一个与先多夫猜想有关的结果
Sendov猜想断言,如果$p(z) = \prod_{j=1}^{N}(z-z_j)$是一个带零的多项式$|z_j| \leq 1$,那么每个磁盘$|z-z_j| \leq 1$包含一个零$p'$。我们的目的如下:给定订单$n \geq 2$的零$z_j$,确定是否存在$\zeta \not= z_j$,以便$p'(\zeta) = 0$和$|z_j - \zeta| \leq 1$。本文给出了该问题的部分结果。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
CiteScore
0.90
自引率
20.00%
发文量
19
审稿时长
6 months
期刊介绍: Annales Polonici Mathematici is a continuation of Annales de la Société Polonaise de Mathématique (vols. I–XXV) founded in 1921 by Stanisław Zaremba. The journal publishes papers in Mathematical Analysis and Geometry. Each volume appears in three issues.
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