Why it is sufficient to consider only the case where the seed of linear cellular automata is $1$

Akane Kawaharada
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Abstract

When using a cellular automaton (CA) as a fractal generator, consider orbits from the single site seed, an initial configuration that gives only a single cell a positive value. In the case of a two-state CA, since the possible states of each cell are $0$ or $1$, the "seed" in the single site seed is uniquely determined to be the state $1$. However, for a CA with three or more states, there are multiple candidates for the seed. For example, for a $3$-state CA, the possible states of each cell are $0$, $1$, and $2$, so the candidates for the seed are $1$ and $2$. For a $4$-state CA, the possible states of each cell are $0$, $1$, $2$, and $3$, so the candidates for the seed are $1$, $2$, and $3$. Thus, as the number of possible states of a CA increases, the number of seed candidates also increases. In this paper, we prove that for linear CAs it is sufficient to consider only the orbit from the single site seed with the seed $1$.
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为什么只考虑线性元胞自动机的种子是$1$的情况就足够了
当使用元胞自动机(CA)作为分形生成器时,考虑来自单个位点种子的轨道,这是一个初始配置,只给单个细胞一个正值。在双状态CA的情况下,由于每个单元的可能状态为$0$或$1$,因此单站点种子中的“种子”被唯一地确定为状态$1$。但是,对于具有三个或更多状态的CA,种子有多个候选项。例如,对于$3$状态的CA,每个cell的可能状态为$0$、$1$和$2$,因此种子的候选值为$1$和$2$。对于$4$状态的CA,每个cell的可能状态为$0$、$1$、$2$和$3$,因此种子的候选值为$1$、$2$和$3$。因此,随着CA可能状态数量的增加,种子候选数量也会增加。在本文中,我们证明了对于线性CAs只考虑从单点种子出发的轨道是足够的。
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