Properties of Laplace-Stieltjes-type integrals

Q3 Mathematics Matematychni Studii Pub Date : 2023-12-18 DOI:10.30970/ms.60.2.115-131
M. M. Sheremeta
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引用次数: 0

Abstract

The properties of Laplace-Stieltjes-type integrals $I(r)=\int_{0}^{\infty}a(x)f(xr)dF(x)$ are studied, where $F$ is a non-negative non-decreasing unbounded continuous on the right function on $[0,\,+\infty)$,$f(z)=\sum_{k=0}^{\infty}f_kz^k$ is an entire transcendental function with $f_k\ge 0$ for all $k\ge0$, and a function $a(x)\ge 0$ on $[0,\,+\infty)$ is such that the Lebesgue-Stieltjes integral $\int_{0}^{K}a(x)f(xr)dF(x)$ exists for every $r\ge 0$ and$K \in [0,\,+\infty)$.For the maximum of the integrand $\mu(r)=\sup\{a(x)f(xr)\colon x\ge 0\}$ it is proved that if$$\varliminf\limits_{x\to+\infty}\frac{f^{-1}\left(1/a(x)\right)}{x}=R_{\mu}$$ then $\mu(r)<+\infty$ for $rR_{\mu}$. The relationship between $R_{\mu}$ and the radius $R_c$ of convergence of the integral $I(r)$ was found. The concept of the central point $\nu(r)$ of the maximum of the integrand is introduced and the formula for finding $\ln \mu(r)$ over $\nu(r)$ is proved.Under certain conditions on the function $F$, estimates of $I(r)$ in terms of $\mu(r)$ are obtained, and in the case when $R_{\mu}=+\infty$,in terms of generalized orders, a relation is established between the growth $\mu(r)$ and $I(r)$ and the decrease of the function $a(x)$.
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拉普拉斯-斯蒂尔杰斯型积分的性质
研究了拉普拉斯-斯蒂尔杰斯型积分$I(r)=\int_{0}^{\infty}a(x)f(xr)dF(x)$的性质,其中$F$是$[0,\,+\infty)$上的非负非递减无界连续右函数、$f(z)=\sum_{k=0}^{\infty}f_kz^k$是一个对所有$k\ge0$都为$f_k\ge 0$的全超越函数,并且在$[0,\,+\infty)$上有一个函数$a(x)\ge 0$、\,+\infty)$上的函数$a(x)ge 0$是这样的:对于每一个$r\ge 0$和$K\in [0,\,+\infty)$,都存在Lebesgue-Stieltjes积分$\int_{0}^{K}a(x)f(xr)dF(x)$。对于积分的最大值$\mu(r)=\sup\{a(x)f(xr)\colon x\ge 0\}$ 可以证明,如果$$\varliminf\limits_{x\to\+\infty}\frac{f^{-1}left(1/a(x)\right)}{x}=R_{\mu}$,那么对于$rR_{mu}$,$\mu(r)<+\infty$。找到了 $R_\{mu}$ 与积分 $I(r)$ 收敛半径 $R_c$ 之间的关系。引入了积分最大值的中心点 $\nu(r)$ 的概念,并证明了在 $\nu(r)$ 上求 $\ln \mu(r)$ 的公式。在函数 $F$ 的某些条件下,得到了以 $\mu(r)$ 为单位的 $I(r)$ 的估计值,并且在 $R_\{mu}=+\infty$ 的情况下,以广义阶数为单位,建立了函数 $a(x)$ 的增长 $\mu(r)$ 和 $I(r)$ 之间的关系。
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来源期刊
Matematychni Studii
Matematychni Studii Mathematics-Mathematics (all)
CiteScore
1.00
自引率
0.00%
发文量
38
期刊介绍: Journal is devoted to research in all fields of mathematics.
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