In this article, we prove the following result. Let n≥3n\ge 3 be some fixed integer and let RR be a prime ring with char(R)≠(n+1)!2n−2{\rm{char}}\left(R)\ne \left(n+1)\!{2}^{n-2}. Suppose there exists an additive mapping D:R→RD:R\to R satisfying the relation 2n−2D(xn)=∑i=0n−2n−2ixiD(x2)xn−2−i+(2n−2−1)(D(x)xn−1+xn−1D(x))+∑i=1n−2∑k=2i(2k−1−1)n−k−2i−k+∑k=2n−1−i(2k−1−1)n−k−2n−i−k−1xiD(x)xn−1−i\begin{array}{rcl}{2}^{n-2}D\left({x}^{n})& =& \left(\mathop{\displaystyle \sum }\limits_{i=0}^{n-2}\left(\genfrac{}{}{0.0pt}{}{n-2}{i}\right){x}^{i}D\left({x}^{2}){x}^{n-2-i}\right)+\left({2}^{n-2}-1)\left(D\left(x){x}^{n-1}+{x}^{n-1}D\left(x))\\ & & +\mathop{\displaystyle \sum }\limits_{i=1}^{n-2}\left(\mathop{\displaystyle \sum }\limits_{k=2}^{i}\left({2}^{k-1}-1)\left(\genfrac{}{}{0.0pt}{}{n-k-2}{i-k}\right)+\mathop{\displaystyle \sum }\limits_{k=2}^{n-1-i}\left({2}^{k-1}-1)\left(\genfrac{}{}{0.0pt}{}{n-k-2}{n-i-k-1}\right)\right){x}^{i}D\left(x){x}^{n-1-i}\end{array} for all x∈R.x\in R. In this case, DD is a derivation. This result is related to a classical result of Herstein, which states that any Jordan derivation on a prime ring with char(R)≠2{\rm{char}}\left(R)\ne 2 is a derivation.
在本文中,我们将证明以下结果。设 n ≥ 3 n\ge 3 是某个固定整数,设 R R 是质环,char ( R ) ≠ ( n + 1 ) ! 2 n - 2 {\rm{char}}\left(R)\ne \left(n+1)\!{2}^{n-2} 。假设存在一个加法映射 D : R → R D:R\to R 满足关系式 2 n - 2 D ( x n ) = ∑ i = 0 n - 2 n - 2 i x i D ( x 2 ) x n - 2 - i + ( 2 n - 2 - 1 ) ( D ( x ) x n - 1 + x n - 1 D ( x ) ) + ∑ i = 1 n - 2 ∑ k = 2 i ( 2 k - 1 - 1 ) n - k - 2 i - k + ∑ k = 2 n - 1 - i ( 2 k - 1 - 1 ) n - k - 2 n - i - k - 1 x i D ( x ) x n - 1 - i \begin{array}{rcl}{2}^{n-2}D\left({x}^{n})&;=& \left(\mathop{displaystyle \sum }\limits_{i=0}^{n-2}\left(\genfrac{}{}{0.0pt}{}{n-2}{i}\right){x}^{i}D\left({x}^{2}){x}^{n-2-i}\right)+\left({2}^{n-2}-1)\left(D\left(x){x}^{n-1}+{x}^{n-1}D\left(x))\\ & &+\mathop{\displaystyle \sum }\limits_{i=1}^{n-2}\left(\mathop{\displaystyle \sum }\limits_{k=2}^{i}\left({2}^{k-1}-1)\left(\genfrac{}{}{0.0pt}{}{n-k-2}{i-k}\right)+\mathop{\displaystyle \sum }\limits_{k=2}^{n-1-i}\left({2}^{k-1}-1)\left(\genfrac{}{}{0.0pt}{}{n-k-2}{n-i-k-1}\right){x}^{i}D\left(x){x}^{n-1-i}\end{array} for all x∈ R. x\in R. In this case, D D is a derivation.这个结果与赫斯坦的一个经典结果有关,它指出在质环上任何char ( R ) ≠ 2 {\rm{char}}\left(R)\ne 2 的乔丹导数都是一个导数。
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