Lengths of factorizations of integer-valued polynomials on Krull domains with prime elements

IF 0.5 4区 数学 Q3 MATHEMATICS Archiv der Mathematik Pub Date : 2024-06-07 DOI:10.1007/s00013-024-02001-0
Victor Fadinger-Held, Daniel Windisch
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Abstract

Let D be a Krull domain admitting a prime element with finite residue field and let K be its quotient field. We show that for all positive integers k and \(1 < n_1 \le \cdots \le n_k\), there exists an integer-valued polynomial on D, that is, an element of \({{\,\textrm{Int}\,}}(D) = \{ f \in K[X] \mid f(D) \subseteq D \}\), which has precisely k essentially different factorizations into irreducible elements of \({{\,\textrm{Int}\,}}(D)\) whose lengths are exactly \(n_1, \ldots , n_k\). Using this, we characterize lengths of factorizations when D is a unique factorization domain and therefore also in case D is a discrete valuation domain. This solves an open problem proposed by Cahen, Fontana, Frisch, and Glaz.

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有素数元素的 Krull 域上整值多项式因式分解的长度
设 D 是一个克鲁尔域,包含一个具有有限残差域的素元,K 是它的商域。我们证明,对于所有正整数 k 和 \(1 <;n_1 \le \cdots \le n_k\),在 D 上存在一个整数值多项式,即 \({{\,\textrm{Int}\,}}(D) = \{ f \in K[X] \mid f(D) \subseteq D \}\)的一个元素、其中恰好有 k 个本质上不同的因式分解为 \({{\,\textrm{Int}\,}}(D)\) 的不可还原元素,它们的长度恰好是 \(n_1, \ldots , n_k\)。利用这一点,我们可以描述当 D 是唯一因式分解域时因式分解的长度,因此也可以描述当 D 是离散估值域时因式分解的长度。这解决了卡亨、方塔纳、弗里施和格拉兹提出的一个未决问题。
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来源期刊
Archiv der Mathematik
Archiv der Mathematik 数学-数学
CiteScore
1.10
自引率
0.00%
发文量
117
审稿时长
4-8 weeks
期刊介绍: Archiv der Mathematik (AdM) publishes short high quality research papers in every area of mathematics which are not overly technical in nature and addressed to a broad readership.
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