Ultrametric-preserving functions as monoid endomorphisms

Oleksiy Dovgoshey
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引用次数: 0

Abstract

Let $\mathbb{R}^{+}=[0, \infty)$ and let $\mathbf{End}_{\mathbb{R}^+}$ be the set of all endomorphisms of the monoid $(\mathbb{R}^+, \vee)$. The set $\mathbf{End}_{\mathbb{R}^+}$ is a monoid with respect to the operation of the function composition $g \circ f$. It is shown that $g : \mathbb{R}^+ \to \mathbb{R}^+$ is pseudometric-preserving iff $g \in \mathbf{End}_{\mathbb{R}^+}$. In particular, a function $f : \mathbb{R}^+ \to \mathbb{R}^+$ is ultrametric-preserving iff it is an endomorphism of $(\mathbb{R}^+,\vee)$ with kelnel consisting only the zero point. We prove that a given $\mathbf{A} \subseteq \mathbf{End}_{\mathbb{R}^+}$ is a submonoid of $(\mathbf{End}, \circ)$ iff there is a class $\mathbf{X}$ of pseudoultrametric spaces such that $\mathbf{A}$ coincides with the set of all functions which preserve the spaces from $\mathbf{X}$. An explicit construction of such $\mathbf{X}$ is given.
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超对称保值函数作为单复数的内态性
让 $\mathbb{R}^{+}=[0, \infty)$,并让 $\mathbf{End}_{\mathbb{R}^+}$ 是单元$(\mathbb{R}^+, \vee)$的所有内变形的集合。集合$mathbf{End}_{\mathbb{R}^+}$ 是关于函数组成操作 $g \circ f$ 的单元。我们可以证明 $g :\mathbb{R}^+ \to\mathbb{R}^+$ 是伪几何保全的,如果 $g \in\mathbf{End}_{\mathbb{R}^+}$ 是这样的话。特别是,函数 $f :\如果它是$(\mathbb{R}^+,\vee)$的内同态,且其kelnel只由零点组成,那么它就是超计量保值的。我们证明给定的 $\mathbf{A}\是$(\mathbf{End}, \circ)$的子单体,如果存在一类$\mathbf{X}$的伪线性空间,使得$\mathbf{A}$与从$\mathbf{X}$保留空间的所有函数的集合重合。本文给出了这种$mathbf{X}$的明确构造。
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