Comment on "Which is greater: $e^π$ or $π^{e}$? An unorthodox physical solution to a classic puzzle"

Roderick M. Macrae
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Abstract

In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and Bove provide a physical argument based nominally on the second law of thermodynamics as a way of resolving the mathematical question appearing in the title. A remarkable aspect of their argument is that it does not depend on the numerical value of $\pi$, because $e^{x} \ge x^{e}$ for all positive $x$, with equality occurring only when $x = e$. Moreover, their argument does not depend on the validity of the second law but is rather a limited proof of it for this particular case.
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关于"$e^π$和$π^{e}$哪个更大?经典难题的非正统物理解决方案"
在最近的一篇注释(《美国物理学杂志》92:397, 2024; arXiv:2309.10826)中,Vallejo和Bove提供了一个名义上基于热力学第二定律的物理论证,以此来解决标题中出现的数学问题。他们的论证的一个显著特点是,它并不依赖于 $\pi$ 的数值,因为 $e^{x}\g x^{e}$,而只有当 $x = e$ 时才会出现质量。此外,他们的论证并不依赖于第二定律的有效性,而是对这一特定情况的有限证明。
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