{"title":"Comment on \"Which is greater: $e^π$ or $π^{e}$? An unorthodox physical solution to a classic puzzle\"","authors":"Roderick M. Macrae","doi":"arxiv-2407.09568","DOIUrl":null,"url":null,"abstract":"In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and\nBove provide a physical argument based nominally on the second law of\nthermodynamics as a way of resolving the mathematical question appearing in the\ntitle. A remarkable aspect of their argument is that it does not depend on the\nnumerical value of $\\pi$, because $e^{x} \\ge x^{e}$ for all positive $x$, with\nequality occurring only when $x = e$. Moreover, their argument does not depend\non the validity of the second law but is rather a limited proof of it for this\nparticular case.","PeriodicalId":501482,"journal":{"name":"arXiv - PHYS - Classical Physics","volume":"32 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-07-08","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - PHYS - Classical Physics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2407.09568","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and
Bove provide a physical argument based nominally on the second law of
thermodynamics as a way of resolving the mathematical question appearing in the
title. A remarkable aspect of their argument is that it does not depend on the
numerical value of $\pi$, because $e^{x} \ge x^{e}$ for all positive $x$, with
equality occurring only when $x = e$. Moreover, their argument does not depend
on the validity of the second law but is rather a limited proof of it for this
particular case.