Edoardo Ballico, Maria Chiara Brambilla, Claudio Fontanari
{"title":"Terracini loci and a codimension one Alexander-Hirschowitz theorem","authors":"Edoardo Ballico, Maria Chiara Brambilla, Claudio Fontanari","doi":"arxiv-2407.18751","DOIUrl":null,"url":null,"abstract":"The Terracini locus $\\mathbb{T}(n, d; x)$ is the locus of all finite subsets\n$S \\subset \\mathbb{P}^n$ of cardinality $x$ such that $\\langle S \\rangle =\n\\mathbb{P}^n$, $h^0(\\mathcal{I}_{2S}(d)) > 0$, and $h^1(\\mathcal{I}_{2S}(d)) >\n0$. The celebrated Alexander-Hirschowitz Theorem classifies the triples\n$(n,d,x)$ for which $\\dim\\mathbb{T}(n, d; x)=xn$. Here we fully characterize\nthe next step in the case $n=2$, namely, we prove that $\\mathbb{T}(2,d;x)$ has\nat least one irreducible component of dimension $2x-1$ if and only if either\n$(d,x)=(6,10)$ or $(d,x)=(4,4)$ or $d\\equiv 1,2 \\pmod{3}$ and $x=(d+2)(d+1)/6$.","PeriodicalId":501475,"journal":{"name":"arXiv - MATH - Commutative Algebra","volume":"78 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-07-26","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - MATH - Commutative Algebra","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2407.18751","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
The Terracini locus $\mathbb{T}(n, d; x)$ is the locus of all finite subsets
$S \subset \mathbb{P}^n$ of cardinality $x$ such that $\langle S \rangle =
\mathbb{P}^n$, $h^0(\mathcal{I}_{2S}(d)) > 0$, and $h^1(\mathcal{I}_{2S}(d)) >
0$. The celebrated Alexander-Hirschowitz Theorem classifies the triples
$(n,d,x)$ for which $\dim\mathbb{T}(n, d; x)=xn$. Here we fully characterize
the next step in the case $n=2$, namely, we prove that $\mathbb{T}(2,d;x)$ has
at least one irreducible component of dimension $2x-1$ if and only if either
$(d,x)=(6,10)$ or $(d,x)=(4,4)$ or $d\equiv 1,2 \pmod{3}$ and $x=(d+2)(d+1)/6$.