A simple quadratic kernel for Token Jumping on surfaces

Daniel W. Cranston, Moritz Mühlenthaler, Benjamin Peyrille
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Abstract

The problem \textsc{Token Jumping} asks whether, given a graph $G$ and two independent sets of \emph{tokens} $I$ and $J$ of $G$, we can transform $I$ into $J$ by changing the position of a single token in each step and having an independent set of tokens throughout. We show that there is a polynomial-time algorithm that, given an instance of \textsc{Token Jumping}, computes an equivalent instance of size $O(g^2 + gk + k^2)$, where $g$ is the genus of the input graph and $k$ is the size of the independent sets.
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表面令牌跳跃的简单二次核
令牌跳转问题(\textsc{Token Jumping})问的是,如果给定一个图 $G$,以及 $G$ 的两个独立的令牌集 $I$ 和 $J$,我们是否可以通过在每一步中改变一个令牌的位置,并在整个过程中拥有一个独立的令牌集,从而将 $I$ 转换成 $J$。我们证明,有一种多项式时间算法可以在给定一个 \textsc{Token Jumping} 实例的情况下,计算出一个大小为 $O(g^2+gk+k^2)$的等价实例,其中 $g$ 是输入图的属,$k$ 是独立集的大小。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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