Δ-Bis[(S)-2-(4-isopropyl-4,5-di­hydro­oxazol-2-yl)phenolato-κ2N,O1](1,10-phenanthroline-κ2N,N′)ruthenium(III) hexa­fluorido­phosphate

IUCrData Pub Date : 2024-09-01 DOI:10.1107/S2414314624008939
Monsuru T. Kelani , Alfred Muller , Koop Lammertsma
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Abstract

The title compound is an example for a chiral-at-metal complex, with the RuIII atom having an octa­hedral coordination environment by three bidentate ligands.
The title compound, [Ru(C12H14NO2)2(C12H8N2)]PF6 crystallizes in the tetra­gonal Sohnke space group P41212. The two bidentate chiral salicyloxazoline ligands and the phenanthroline co-ligand coordinate to the central RuIII atom through N,O and N,N atom pairs to form bite angles of 89.76 (15) and 79.0 (2)°, respectively. The octa­hedral coordination of the bidentate ligands leads to a propeller-like shape, which induces metal-centered chirality onto the complex, with a right-handed (Δ) absolute configuration [the Flack parameter value is −0.003 (14)]. Both the complex cation and the disordered PF6 counter-anion are located on twofold rotation axes. Apart from Coulombic forces, the crystal cohesion is ensured by non-classical C—H⋯O and C—H⋯F inter­actions.
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Δ-双[(S)-2-(4-异丙基-4,5-二氢-恶唑-2-基)苯酚基-κ2 N,O 1](1,10-菲罗啉-κ2 N,N')六氟磷酸钌(III)。
标题化合物[Ru(C12H14NO2)2(C12H8N2)]PF6 在 P41212 四元索恩科空间群中结晶。两个二价手性水杨酰噁唑啉配体和菲罗啉共配体通过 N、O 和 N、N 原子对与中心 RuIII 原子配位,分别形成 89.76 (15) 和 79.0 (2) ° 的咬合角。双齿配体的八面体配位形成了类似螺旋桨的形状,从而使配合物具有以金属为中心的手性,绝对构型为右旋(Δ)[Flack 参数值为 -0.003 (14)]。复合物阳离子和无序的 PF6 - 对阴离子都位于两倍旋转轴上。除了库仑力之外,非典型的 C-H⋯O 和 C-H⋯F 相互作用也确保了晶体的内聚力。
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[(1,2,5,6-η)-Cyclo­octa-1,5-diene](1-ethyl-4-iso­butyl-1,2,4-triazol-5-yl­idene)(tri­phenyl­phosphane)iridium(I) tetra­fluorido­borate di­chloro­methane hemisolvate C-type Yb2Te3O9 catena-Poly[[(8-amino­quinoline)­cobalt(II)]-di-μ-azido] 2-Bromo­acetamide Bis[2-(isoquinolin-1-yl)phenyl-κ2N,C1](2-phenyl-1H-imidazo[4,5-f][1,10]phenanthroline-κ2N,N′)iridium(III) hexa­fluorido­phosphate methanol monosolvate
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