Equilibrium stacks for a three-person game on a product of staircase-function continuous and finite strategy spaces

IF 1.8 Q3 COMPUTER SCIENCE, ARTIFICIAL INTELLIGENCE Foundations of Computing and Decision Sciences Pub Date : 2022-02-01 DOI:10.2478/fcds-2022-0002
V. Romanuke
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Abstract

Abstract A method of solving a three-person game defined on a product of staircase-function strategy spaces is presented. The spaces can be finite and continuous. The method is based on stacking equilibria of “short” three-person games, each defined on an interval where the pure strategy value is constant. In the case of finite three-person games, which factually are trimatrix games, the equilibria are considered in general terms, so they can be in mixed strategies as well. The stack is any interval-wise combination (succession) of the respective equilibria of the “short” trimatrix games. Apart from the stack, there are no other equilibria in this “long” trimatrix game. An example is presented to show how the stacking is fulfilled for a case of when every “short” trimatrix game has a pure-strategy equilibrium. The presented method, further “breaking” the initial “long” game defined on a product of staircase-function finite spaces, is far more tractable than a straightforward approach to solving directly the “long” trimatrix game would be.
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阶梯函数连续和有限策略空间积上的三人博弈的均衡堆栈
摘要给出了一种在阶梯函数策略空间积上定义的三人对策的求解方法。空间可以是有限的和连续的。该方法基于“短”三人博弈的堆叠均衡,每个博弈在纯策略值恒定的区间内定义。在有限三人博弈的情况下,实际上是三矩阵博弈,均衡被认为是一般的,所以它们也可以是混合策略。堆栈是“短”三矩阵对策的各自均衡的任意间隔组合(连续)。除了堆栈,在这个“长”三矩阵博弈中没有其他均衡。给出了一个例子,说明当每个“短”三矩阵对策都具有纯策略均衡时,如何实现堆叠。所提出的方法,进一步“打破”在阶梯函数有限空间的乘积上定义的初始“长”博弈,比直接解决“长”三矩阵博弈的直接方法要容易得多。
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来源期刊
Foundations of Computing and Decision Sciences
Foundations of Computing and Decision Sciences COMPUTER SCIENCE, ARTIFICIAL INTELLIGENCE-
CiteScore
2.20
自引率
9.10%
发文量
16
审稿时长
29 weeks
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