The Galois group of X^{p^2}+aX+a

Q4 Mathematics Mathematica Pub Date : 2023-06-15 DOI:10.24193/mathcluj.2023.1.12
Soufyane Mokhtari, Boualem Benseba
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引用次数: 0

Abstract

Let p be an odd prime number, and a be an integer divisible by p exactly once. We prove that the Galois group G of the trinomial X^{p^{2}}+aX+a over the field Q of rational number is either the full symmetric group S_{p^{2}} or G lies between AGL(1,p^{2}) and AGL(2,p)$. Furthermore, we establish conditions when G is S_{p^{2}}.
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X^ (p^2) +aX+a的伽罗瓦群
设p是奇质数,a是能被p整除一次的整数。证明了有理数域Q上三项式X^{p^{2}}+aX+a的伽罗瓦群G是满对称群S_{p^{2}}或者G位于AGL(1,p^{2})和AGL(2,p)$之间。进一步,我们建立了G为S_{p^{2}}的条件。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
Mathematica
Mathematica Mathematics-Mathematics (all)
CiteScore
0.30
自引率
0.00%
发文量
17
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