ELECTROCHEMICAL OXIDATION OF DIMETHYL SULFONE IN ALKALINE MEDIUM

M. Akhmedov, S. Khidirov, Madina Yu. Kaparova
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引用次数: 2

Abstract

In this paper the electrochemical oxidation of dimethyl sulfone (DMSO2) on a platinum electrode in an alkaline medium has been studied by cyclic voltammetry. It is shown that during the electrochemical oxidation of dimethylsulfone in an alkaline medium on a smooth platinum electrode, a significant suppression of the oxygen evolution (O2) occurs in the potential range of E = 1.3-2.0 V. By scanning electron microscopy methods, Raman scattering and infrared spectrometry it is shown that the main substance is the dimethyl disulfone (DMDSO2) during the anodic oxidation of DMSO2 on a platinum electrode. By the preparative electrolysis of aqueous solutions of various concentrations of DMSO2 in 0.1 M NaOH solution at controlled potentials E = 1.6 and 1.8 V it is established that the current yield of the base material is not more than 84%. Based on the data of the physicochemical analysis of the final products of preparative electrolysis, a mechanism is proposed for the formation of dimethyl disulfone in an alkaline medium. It has been shown that the oxidation of dimethyl sulfone proceeds in the oxygen region by breaking C-S bonds in the DMSO2 molecule to form methyl (CH3•) and methylsulfonic (CH3S•(O)2) radicals. It is assumed that the methylsulfone radicals readily dimerize with the formation of stable DMDSO2 molecules and are desorbed in the bulk of the solution, and the methyl radicals bind to the HO radicals to form methanol molecules. The latter is well chemisorbed on the surface of platinum with the formation of adsorbed COH particles that are oxidized on a platinum electrode with the formation and evolution of carbon dioxide (CO2) from the volume of the anolyte solution. The formation of molecules of methanol was identified by the method of chromato-mass -spectrometry, and the emission of carbon dioxide by the gravimetry.
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二甲基砜在碱性介质中的电化学氧化
本文用循环伏安法研究了二甲基砜(DMSO2)在碱性介质中铂电极上的电化学氧化。结果表明,在光滑铂电极上,二甲基砜在碱性介质中电化学氧化时,在E = 1.3 ~ 2.0 V电位范围内,析氧(O2)受到明显抑制。通过扫描电镜、拉曼散射和红外光谱分析表明,DMSO2在铂电极上阳极氧化的主要物质是二甲基二砜(DMDSO2)。通过控制电势E = 1.6和1.8 V,在0.1 M NaOH溶液中对不同浓度的DMSO2水溶液进行电解制备,确定了基材的电流产率不大于84%。根据制备电解终产物的理化分析数据,提出了在碱性介质中生成二甲基二砜的机理。研究表明,二甲基砜的氧化是在氧区进行的,通过破坏DMSO2分子中的C-S键形成甲基(CH3•)和甲基磺酸(CH3S•(O)2)自由基。假设甲基砜自由基容易二聚化,形成稳定的DMDSO2分子,并在大部分溶液中被解吸,甲基自由基与HO自由基结合形成甲醇分子。后者在铂表面被很好地化学吸附,形成吸附的COH颗粒,随着阳极液溶液体积中二氧化碳的形成和演化,COH颗粒在铂电极上被氧化。用质谱法测定了甲醇分子的形成,用重量法测定了二氧化碳的释放。
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来源期刊
CiteScore
1.40
自引率
44.40%
发文量
83
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