(0,1)-matrices and Discrepancy

Pub Date : 2021-11-18 DOI:10.13001/ela.2021.5033
LeRoy B. Beasley
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引用次数: 0

Abstract

 Let $m$ and $n$ be positive integers, and let $R =(r_1, \ldots, r_m)$ and $S =(s_1,\ldots, s_n)$ be nonnegative integral vectors. Let $A(R,S)$ be the set of all $m \times n$ $(0,1)$-matrices with row sum vector $R$ and column vector $S$. Let $R$ and $S$ be nonincreasing, and let $F(R)$ be the $m \times n$ $(0,1)$-matrix where for each $i$, the $i^{th}$ row of $F(R,S)$ consists of $r_i$ 1's followed by $n-r_i$ 0's. Let $A\in A(R,S)$. The discrepancy of A, $disc(A)$, is the number of positions in which $F(R)$ has a 1 and $A$ has a 0. In this paper, we investigate the possible discrepancy of $A^t$ versus the discrepancy of $A$. We show that if the discrepancy of $A$ is $\ell$, then the discrepancy of the transpose of $A$ is at least $\frac{\ell}{2}$ and at most $2\ell$. These bounds are tight.
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(0,1)-矩阵与差异
设$m$和$n$为正整数,设$R =(r_1, \ldots, r_m)$和$S =(s_1,\ldots, s_n)$为非负积分向量。设$A(R,S)$是所有$m \乘以n$ $(0,1)$-具有行和向量$R$和列向量$S$的矩阵的集合。设$R$和$S$是非递增的,设$F(R)$是$m \乘以n$ $(0,1)$-矩阵,其中对于每个$i$, $F(R,S)$的$i^{th}$行由$r_i$ 1和$n-r_i$ 0组成。设$A\在A(R,S)$中。A的差异$disc(A)$是$F(R)$为1而$A$为0的位置数。本文研究了A^t$与A$的可能差异。我们证明了如果$A$的差值为$\ell$,则$A$的转置差值至少为$\frac{\ell}{2}$,最多为$2\ell$。这些界限很紧。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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