S-shaped component of nodal solutions for problem involving one-dimension mean curvature operator

IF 0.4 4区 数学 Q4 MATHEMATICS Czechoslovak Mathematical Journal Pub Date : 2023-03-08 DOI:10.21136/CMJ.2023.0027-20
Ruyun Ma, Zhiqian He, Xiaoxiao Su
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引用次数: 0

Abstract

Let E = {u ∈ C1[0, 1]: u(0) = u(1) = 0}. Let Skv with v = {+, −} denote the set of functions u ∈ E which have exactly k − 1 interior nodal zeros in (0, 1) and vu be positive near 0. We show the existence of S-shaped connected component of Skv-solutions of the problem {(u′1−u′2)′+λa(x)f(u)=0,x∈(0,1),u(0)=u(1)=0,\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document}$$\left\{ {\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} {{{\left( {\frac{{u'}}{{\sqrt {1 - {{u'}^2}} }}} \right)}^\prime } + \lambda a(x)f(u) = 0,}&{x \in (0,1)} \end{array}} \\ {u(0) = u(1) = 0,\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;} \end{array}} \right.$$\end{document} where λ > 0 is a parameter, a ∈ C([0, 1], (0, ∞)). We determine the intervals of parameter λ in which the above problem has one, two or three Skv-solutions. The proofs of the main results are based upon the bifurcation technique.
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一维平均曲率算子问题节点解的S形分量
设E={u∈C1[0,1]:u(0)=u(1)=0}。设v={+,−}的Skv表示函数u∈E的集合,其在(0,1)中正好有k−1个内部节点零,并且vu在0附近为正。我们证明了问题{(u′1−u′2)′+λa(x)f(u)=0,x∈(0,1),u(0)=u(1)=0,\documentclass[12pt]{minimal}\usepackage{amsmath}\usepackage{wasysym}\ usepackage{amsfonts}\usecpackage{amssymb}\userpackage{{amsbsy}\usecpackage{mathrsfs}\usepackage{upgek}\setlength左开始数组{c} }{\begin{array}{{*{20}}{c}}{{\left({\frac{u’})}{\;\;;\;}\end{array}}\right$$\end{document}其中λ>0是一个参数,a∈C([0,1],(0,∞))。我们确定参数λ的区间,其中上述问题具有一个、两个或三个Skv解。主要结果的证明是基于分叉技术。
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来源期刊
CiteScore
0.90
自引率
0.00%
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0
审稿时长
6-12 weeks
期刊介绍: Czechoslovak Mathematical Journal publishes original research papers of high scientific quality in mathematics.
期刊最新文献
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