Phenazine and 10H-phenothiazine cocrystal stabilized by N-H···N and C-H···S hydrogen bonds

T. Mehmood, Bhumiben Chandubhai Patel, J. P. Reddy
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Abstract

A 1:1 co-crystal of phenazine and phenothiazine was prepared. The crystal structure was determined by using a single crystal X-ray crystallography technique. Analysis of the crystal revealed that the molecular complex crystallizes in monoclinic P21/n space group, C12H8N2·C12H9NS, a = 9.068(2) Å, b = 8.872(2) Å, c = 23.935(4) Å, β = 92.16(4)°, V = 1924.1(6) Å3, Z = 4, T = 293(2) K, μ(MoKα) = 0.182 mm-1, Dcalc = 1.310 g/cm3, 8057 reflections measured (3.4° ≤ 2Θ ≤ 46.54°), 2751 unique (Rint = 0.0559, Rsigma = 0.0618) which were used in all calculations. The final R1 was 0.0548 (>2sigma(I)) and wR2 was 0.1029 (all data). The molecules recognize each other through N-H···N and C-H···N hydrogen bonds, thus producing a tetramer unit. These units further interact with one another via C-H···S hydrogen bonds.
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由N-H··N和C-H··S氢键稳定的吩嗪和10H-吩噻嗪共晶
制备了吩嗪和吩噻嗪的1:1共晶。晶体结构是用单晶X射线晶体学技术测定的。晶体分析表明,分子配合物结晶于单斜P21/n空间群,C12H8N2·C12H9NS,a=9.068(2)Å,b=8.872(2)å,c=23.935(4)Å、β=92.16(4)°,V=1924.1(6)Å3,Z=4,T=293(2)K,μ(MoKα)=0.182 mm-1,Dcalc=1.310 g/cm3,测量到8057次反射(3.4°≤2θ≤46.54°),2751个唯一的(Rint=0.0559,Rsigma=0.0618),其在所有计算中使用。最终R1为0.0548(>2sigma(I)),wR2为0.1029(所有数据)。分子通过N-H·N和C-H·N氢键相互识别,从而产生四聚体单元。这些单元进一步通过C-H··S氢键相互作用。
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