Optimization of co-culture condition with respect to aeration and glucose to xylose ratio for bioethanol production

IF 0.9 Q4 ENGINEERING, CHEMICAL Indian Chemical Engineer Pub Date : 2023-03-04 DOI:10.1080/00194506.2023.2190332
Shashi Kumar, G. Agarwal, T. Sreekrishnan
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Abstract

ABSTRACT The present study was designed to find a suitable microaerobic condition and ratio of glucose and xylose for maximum ethanol production using co-culture of Saccharomyces cerevisiae and Pichia stipitis. The maximum ethanol concentration and yield were achieved at 0.05 vvm aeration rate and 2:1 glucose/xylose ratio. The co-culture resulted in maximum ethanol concentration, ethanol yield, and volumetric productivity of 12.33 ± 0.10 g/L, 0.43 g/g, and 0.26 g/L/h, respectively. While, the monoculture of P. stipitis resulted in 8.96 ± 0.13 g/L, 0.36 g/g, and 0.19 g/L/h respectively. The fermentation carried out in microaerobic mode delivered 10.68% and 10.56% more ethanol concentration and ethanol yield respectively from glucose compared to the combination of anaerobic and microaerobic mode. Also, the glucose uptake rate increased to 0.83 g/L/h, which corresponds to an improvement of 50.16%, suggesting that the lower microaerophilic condition not only supports P. stipitis metabolism but also does S. cerevisiae to convert glucose faster in a co-culture system. Hence, co-culture cultivation in microaerobic mode would be a better condition to achieve maximum ethanol and productivity. GRAPHICAL ABSTRACT
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从曝气和葡萄糖与木糖的比例优化生物乙醇共培养条件
摘要本研究旨在通过酿酒酵母和毕赤酵母的共培养,找到一个合适的微需氧条件以及葡萄糖和木糖的比例,以最大限度地生产乙醇。乙醇的最大浓度和产量为0.05 vvm通气速率和2:1的葡萄糖/木糖比例。共培养产生最大乙醇浓度、乙醇产量和12.33的体积生产率 ± 0.10 g/L,0.43 g/g和0.26 g/L/h。而托叶P.stiptis的单一栽培结果为8.96 ± 0.13 g/L,0.36 g/g和0.19 g/L/h。与厌氧和微需氧模式的组合相比,在微需氧模式下进行的发酵从葡萄糖中获得的乙醇浓度和乙醇产量分别高出10.68%和10.56%。此外,葡萄糖摄取率增加到0.83 g/L/h,这对应于50.16%的改善,这表明较低的微需氧条件不仅支持P.stiptis的代谢,而且使酿酒酵母在共培养系统中更快地转化葡萄糖。因此,在微需氧模式下共培养将是实现最大乙醇和生产力的更好条件。图形摘要
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来源期刊
Indian Chemical Engineer
Indian Chemical Engineer ENGINEERING, CHEMICAL-
CiteScore
3.00
自引率
6.70%
发文量
33
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