Where Some Inert Minimal Ring Extensions of a Commutative Ring Come from

Pub Date : 2020-03-31 DOI:10.5666/KMJ.2020.60.1.53
D. Dobbs
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Abstract

Let (A,M) ⊂ (B,N) be commutative quasi-local rings. We consider the property that there exists a ring D such that A ⊆ D ⊂ B and the extension D ⊂ B is inert. Examples show that the number of such D may be any non-negative integer or infinite. The existence of such D does not imply M ⊆ N . Suppose henceforth that M ⊆ N . If the field extension A/M ⊆ B/N is algebraic, the existence of such D does not imply that B is integral over A (except when B has Krull dimension 0). If A/M ⊆ B/N is a minimal field extension, there exists a unique such D, necessarily given by D = A+N (but it need not be the case that N = MB). The converse fails, even if M = N and B/M is a finite
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交换环的惰性极小环扩展从何而来
设(A,M)⊂(B,N)是可交换的拟局部环。我们考虑存在环D的性质,使得a⊆D \8838B和扩展D \8834B是惰性的。实例表明,这种D的数目可以是任何非负整数或无穷大。这种D的存在并不意味着M⊆N。此后假设M⊆N。如果域扩展A/M⊆B/N是代数的,则这种D的存在并不意味着B是A上的积分(除非B具有Krull维数0)。如果A/M⊆B/N是极小域扩展,则存在唯一的这样的D,必然由D=A+N给出(但不必是N=MB的情况)。反之亦然,即使M=N和B/M是有限的
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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