On the automorphism groups of us-Cayley graphs

S. Mirafzal
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引用次数: 5

Abstract

Let $G$ be a finite abelian group written additively with identity $0$, and $\Omega$ be an inverse closed generating subset of $G$ such that $0\notin \Omega$. We say that $ \Omega $ has the property \lq\lq{}$us$\rq\rq{} (unique summation), whenever for every $0 \neq g\in G$ if there are $s_1,s_2,s_3, s_4 \in \Omega $ such that $s_1+s_2=g=s_3+s_4 $, then we have $\{s_1,s_2 \} = \{s_3,s_4 \}$. We say that a Cayley graph $\Gamma=Cay(G;\Omega)$ is a $us$-$Cayley\ graph$, whenever $G$ is an abelian group and the generating subset $\Omega$ has the property \lq\lq{}$us$\rq\rq{}. In this paper, we show that if $\Gamma=Cay(G;\Omega)$ is a $us$-$Cayley\ graph$, then $Aut(\Gamma)=L(G)\rtimes A$, where $L(G)$ is the left regular representation of $G$ and $A$ is the group of all automorphism groups $\theta$ of the group $G$ such that $\theta(\Omega)=\Omega$. Then, as some applications, we explicitly determine the automorphism groups of some classes of graphs including M\"{o}bius ladders and $k$-ary $n$-cubes.
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关于us-Cayley图的自同构群
让 $G$ 是一个有限阿贝尔群,加性地写有恒等式 $0$,和 $\Omega$ 是的逆闭生成子集 $G$ 这样 $0\notin \Omega$。我们说 $ \Omega $ 拥有财产 \lq\lq{}$us$\rq\rq{} (唯一的和),每当对于每一个 $0 \neq g\in G$ 如果有的话 $s_1,s_2,s_3, s_4 \in \Omega $ 这样 $s_1+s_2=g=s_3+s_4 $,那么我们有 $\{s_1,s_2 \} = \{s_3,s_4 \}$。我们称之为凯莱图 $\Gamma=Cay(G;\Omega)$ 是? $us$-$Cayley\ graph$,每当 $G$ 是一个阿贝尔群和生成子集吗 $\Omega$ 拥有财产 \lq\lq{}$us$\rq\rq{}。在本文中,我们证明了如果 $\Gamma=Cay(G;\Omega)$ 是? $us$-$Cayley\ graph$那么, $Aut(\Gamma)=L(G)\rtimes A$,其中 $L(G)$ 左边的正则表示是 $G$ 和 $A$ 是所有自同构群的群吗 $\theta$ 小组的成员 $G$ 这样 $\theta(\Omega)=\Omega$。然后,作为一些应用,我们显式地确定了一些图的自同构群,包括Möbius阶梯和 $k$-ary $n$-立方体。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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来源期刊
Art of Discrete and Applied Mathematics
Art of Discrete and Applied Mathematics Mathematics-Discrete Mathematics and Combinatorics
CiteScore
0.90
自引率
0.00%
发文量
43
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