{"title":"Curvature tensors of higher-spin gauge theories derived from general Lagrangian densities","authors":"M. R. Baker, Julia Bruce-Robertson","doi":"10.1139/cjp-2020-0623","DOIUrl":null,"url":null,"abstract":"Curvature tensors of higher-spin gauge theories have been known for some time. In the past, they were postulated using a generalization of the symmetry properties of the Riemann tensor (curl on each index of a totally symmetric rank-$n$ field for each spin-$n$). For this reason they are sometimes referred to as the generalized 'Riemann' tensors. In this article, a method for deriving these curvature tensors from first principles is presented; the derivation is completed without any a priori knowledge of the existence of the Riemann tensors or the curvature tensors of higher-spin gauge theories. To perform this derivation, a recently developed procedure for deriving exactly gauge invariant Lagrangian densities from quadratic combinations of $N$ order of derivatives and $M$ rank of tensor potential is applied to the $N = M = n$ case under the spin-$n$ gauge transformations. This procedure uniquely yields the Lagrangian for classical electrodynamics in the $N = M = 1$ case and the Lagrangian for higher derivative gravity (`Riemann' and `Ricci' squared terms) in the $N = M = 2$ case. It is proven here by direct calculation for the $N = M = 3$ case that the unique solution to this procedure is the spin-3 curvature tensor and its contractions. The spin-4 curvature tensor is also uniquely derived for the $N = M = 4$ case. In other words, it is proven here that, for the most general linear combination of scalars built from $N$ derivatives and $M$ rank of tensor potential, up to $N=M=4$, there exists a unique solution to the resulting system of linear equations as the contracted spin-$n$ curvature tensors. Conjectures regarding the solutions to the higher spin-$n$ $N = M = n$ are discussed.","PeriodicalId":8443,"journal":{"name":"arXiv: High Energy Physics - Theory","volume":"34 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2020-10-20","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv: High Energy Physics - Theory","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1139/cjp-2020-0623","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
Curvature tensors of higher-spin gauge theories have been known for some time. In the past, they were postulated using a generalization of the symmetry properties of the Riemann tensor (curl on each index of a totally symmetric rank-$n$ field for each spin-$n$). For this reason they are sometimes referred to as the generalized 'Riemann' tensors. In this article, a method for deriving these curvature tensors from first principles is presented; the derivation is completed without any a priori knowledge of the existence of the Riemann tensors or the curvature tensors of higher-spin gauge theories. To perform this derivation, a recently developed procedure for deriving exactly gauge invariant Lagrangian densities from quadratic combinations of $N$ order of derivatives and $M$ rank of tensor potential is applied to the $N = M = n$ case under the spin-$n$ gauge transformations. This procedure uniquely yields the Lagrangian for classical electrodynamics in the $N = M = 1$ case and the Lagrangian for higher derivative gravity (`Riemann' and `Ricci' squared terms) in the $N = M = 2$ case. It is proven here by direct calculation for the $N = M = 3$ case that the unique solution to this procedure is the spin-3 curvature tensor and its contractions. The spin-4 curvature tensor is also uniquely derived for the $N = M = 4$ case. In other words, it is proven here that, for the most general linear combination of scalars built from $N$ derivatives and $M$ rank of tensor potential, up to $N=M=4$, there exists a unique solution to the resulting system of linear equations as the contracted spin-$n$ curvature tensors. Conjectures regarding the solutions to the higher spin-$n$ $N = M = n$ are discussed.
高自旋规范理论的曲率张量已经被发现有一段时间了。在过去,它们是使用黎曼张量的对称性质的一般化来假设的(完全对称的秩-$n$场的每个指标上的旋度对于每个自旋-$n$)。由于这个原因,它们有时被称为广义黎曼张量。本文给出了一种从第一性原理推导曲率张量的方法;推导是在没有黎曼张量或高自旋规范理论的曲率张量存在的先验知识的情况下完成的。为了进行这一推导,我们将最近发展的一种方法应用于自旋-$ N$规范变换下的$N$阶导数和$M$阶张量势的二次组合中精确地推导出规范不变拉格朗日密度。这个过程唯一地产生了N = M = 1$情况下经典电动力学的拉格朗日量和N = M = 2$情况下高导数引力的拉格朗日量(“黎曼”和“里奇”平方项)。这里通过直接计算证明了$N = M = 3$的情况下,这个过程的唯一解是自旋-3曲率张量及其收缩。自旋-4曲率张量也是在$N = M = 4$的情况下唯一导出的。换句话说,这里证明了,对于由$N$导数和$M$阶张量势构成的最一般的标量线性组合,直到$N=M=4$,作为收缩自旋-$ N$曲率张量的线性方程组存在唯一解。讨论了关于高自旋-$n$ n = M = n$解的猜想。