Chirality effects on 1H and 13C NMR chemical shifts for Aerosol OT in reverse micelles assisted by line shape simulations and two-dimensional pulse techniques

Akihiro Yoshino , Nobuyuki Sugiyama , Hirofumi Okabayashi , Keijiro Taga , Tadayoshi Yoshida , Osamu Kamo
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引用次数: 9

Abstract

For the 1H NMR spectrum of sodium bis(2-ethylhexyl)sulfosuccinate (AOT) in C6D6D2O, the very complex H3′ signals, which have not yet been elucidated, have now been successfully explained by superimposition of the four AB parts, and have been discussed in connection with the diastereoisomers arising from the three asymmetric carbon atoms.

Discussion of the 13C NMR signal assignment of AOT in organic solvents has previously been focused on the signals of the head group (CH(SO3)CH2) and on the CH2OCO and OCH2CH segments. In this study, the signals arising from the other segments of the two chains have been completely assigned to the individual carbon atoms of each 2-ethylhexyl chain, using pulse techniques.

The secondary splitting of the 13C chemical shifts was due to the chirality effect of an AOT molecule. In particular, the effect of the chiral centers was found to be concentrated on the α chain and to reach the C6′carbon.

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在线形模拟和二维脉冲技术的辅助下,手性对气溶胶OT在反胶束中的1H和13C NMR化学位移的影响
对于C6D6D2O中的二(2-乙基己基)琥珀磺酸钠(AOT)的1H NMR谱,通过四个AB部分的叠加已经成功地解释了尚未阐明的非常复杂的H3′信号,并与三个不对称碳原子产生的非对映异构体进行了讨论。关于有机溶剂中AOT的13C核磁共振信号分配的讨论以前主要集中在头基团(CH(SO−3)CH2)和CH2OCO和OCH2CH段的信号上。在本研究中,使用脉冲技术,从两条链的其他部分产生的信号已经完全分配到每个2-乙基己基链的单个碳原子上。13C化学位移的二次分裂是由于AOT分子的手性效应。特别是,手性中心的作用主要集中在α链上,并到达c6′碳。
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