An anti-sum-symmetry model and its orthogonal decomposition for ordinal square contingency tables with an application to grip strength test data

S. Ando
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引用次数: 1

Abstract

Summary For the analysis of R × R square contingency tables, we need to estimate an unknown probability distribution with high confidence from obtained observations. For that purpose, we need to perform the analysis using a statistical model that fits the data well and has a simple interpretation. This study proposes two original models that have symmetric and asymmetric structures between the probability with which the sum of row and column variables is t, for t = 2, . . ., R, and the probability with which the sum of row and column variables is 2(R + 1) − t. The study also reveals that it is necessary to satisfy the anti-global symmetry model, in addition to the proposed asymmetry model, in order to satisfy the proposed symmetry model. This decomposition theorem is useful to explain why the proposed symmetry model does not hold. Moreover, we show that the value of the likelihood ratio chi-squared statistic of the proposed symmetry model is equal to the sum of those of the decomposed models. We evaluate the utility of the proposed models by applying them to real-world grip strength data.
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序方列联表的反和对称模型及其正交分解及其在握力试验数据中的应用
对于R × R平方列联表的分析,我们需要从得到的观测值中估计一个未知的高置信度的概率分布。为此,我们需要使用一个统计模型来执行分析,该模型可以很好地拟合数据并具有简单的解释。本研究提出两个原始模型之间的对称和非对称结构的概率之和的行和列变量t, t = 2,…,R,和概率的总和行和列变量是2 (R + 1)−t。研究还表明,它是必要的,以满足全球对称模型,除了提出不对称模型,为了满足提出的对称模型。这个分解定理有助于解释为什么所提出的对称模型不成立。此外,我们证明了所提出的对称模型的似然比卡方统计量的值等于分解模型的似然比卡方统计量的和。我们通过将所提出的模型应用于实际握力数据来评估其效用。
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