The spread of a finite group

Timothy C. Burness, R. Guralnick, Scott Harper
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引用次数: 32

Abstract

A group $G$ is said to be $\frac{3}{2}$-generated if every nontrivial element belongs to a generating pair. It is easy to see that if $G$ has this property then every proper quotient of $G$ is cyclic. In this paper we prove that the converse is true for finite groups, which settles a conjecture of Breuer, Guralnick and Kantor from 2008. In fact, we prove a much stronger result, which solves a problem posed by Brenner and Wiegold in 1975. Namely, if $G$ is a finite group and every proper quotient of $G$ is cyclic, then for any pair of nontrivial elements $x_1,x_2 \in G$, there exists $y \in G$ such that $G = \langle x_1, y \rangle = \langle x_2, y \rangle$. In other words, $s(G) \geqslant 2$, where $s(G)$ is the spread of $G$. Moreover, if $u(G)$ denotes the more restrictive uniform spread of $G$, then we can completely characterise the finite groups $G$ with $u(G) = 0$ and $u(G)=1$. To prove these results, we first establish a reduction to almost simple groups. For simple groups, the result was proved by Guralnick and Kantor in 2000 using probabilistic methods and since then the almost simple groups have been the subject of several papers. By combining our reduction theorem and this earlier work, it remains to handle the groups whose socles are exceptional groups of Lie type and this is the case we treat in this paper.
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有限群的扩展
如果每个非平凡元素都属于生成对,则称群$G$是$\frac{3}{2}$生成的。很容易看出,如果$G$具有这个性质,那么$G$的每一个固有商都是循环的。本文证明了有限群的逆命题成立,从而解决了Breuer、Guralnick和Kantor在2008年提出的一个猜想。事实上,我们证明了一个更强的结果,它解决了Brenner和Wiegold在1975年提出的一个问题。即,如果$G$是一个有限群,且$G$的每一个真商都是循环的,则对于任意一对非平凡元素$x_1,x_2 \in G$,存在$y \in G$使得$G = \langle x_1, y \rangle = \langle x_2, y \rangle$。也就是说,$s(G) \geqslant 2$,其中$s(G)$是$G$的传播。此外,如果$u(G)$表示$G$的更严格的一致扩展,则我们可以用$u(G) = 0$和$u(G)=1$完全表征有限群$G$。为了证明这些结果,我们首先建立了一个几乎简单群的约简。对于简单群,这个结果在2000年由Guralnick和Kantor用概率方法证明了,从那时起,几乎简单群就成为了几篇论文的主题。通过结合我们的约简定理和之前的工作,它仍然可以处理其群是李型例外群的群,这就是我们在本文中处理的情况。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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