Complexity of (arc)-connectivity problems involving arc-reversals or deorientations

J. Bang-Jensen, Florian Hörsch, M. Kriesell
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引用次数: 1

Abstract

By a well known theorem of Robbins, a graph $G$ has a strongly connected orientation if and only if $G$ is 2-edge-connected and it is easy to find, in linear time, either a cut edge of $G$ or a strong orientation of $G$. A result of Durand de Gevigny shows that for every $k\geq 3$ it is NP-hard to decide if a given graph $G$ has a $k$-strong orientation. Thomassen showed that one can check in polynomial time whether a given graph has a 2-strong orientation. This implies that for a given digraph $D$ we can determine in polynomial time whether we can reorient (=reverse) some arcs of $D=(V,A)$ to obtain a 2-strong digraph $D'=(V,A')$. This naturally leads to the question of determining the minimum number of such arcs to reverse before the resulting graph is 2-strong. In this paper we show that finding this number is NP-hard. If a 2-connected graph $G$ has no 2-strong orientation, we may ask how many of its edges we may orient so that the resulting mixed graph is still 2-strong. Similarly, we may ask for a 2-edge-connected graph $G$ how many of its edges we can orient such that the resulting mixed graph remains 2-arc-strong. We prove that when restricted to graphs satisfying suitable connectivity conditions, both of these problems are equivalent to finding the minimum number of edges we must double in a 2-edge-connected graph in order to obtain a 4-edge-connected graph. Using this, we show that all these three problems are NP-hard. Finally, we consider the operation of deorienting an arc $uv$ of a digraph $D$ meaning replacing it by an undirected edge between the same vertices. In terms of connectivity properties, this is equivalent to adding the opposite arc $vu$ to $D$. We prove that for every $\ell\geq 3$ it is NP-hard to find the minimum number of arcs to deorient in a digraph $D$ in order to obtain an $\ell$-strong digraph $D'$.
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涉及电弧反转或定向的(电弧)连通性问题的复杂性
根据著名的罗宾斯定理,当且仅当$G$是2边连通时,图$G$具有强连通方向,并且在线性时间内很容易找到$G$的切边或$G$的强定向。Durand de Gevigny的结果表明,对于每个$k\geq 3$来说,决定给定图$G$是否具有$k$ -强取向是np困难的。Thomassen证明了可以在多项式时间内检验给定图是否具有2强取向。这意味着对于给定的有向图$D$,我们可以在多项式时间内确定是否可以重新定向(=反转)$D=(V,A)$的一些弧以获得2强有向图$D'=(V,A')$。这自然导致了一个问题,即在生成的图形为2强之前,确定要反转的这种弧线的最小数量。在本文中,我们证明了找到这个数是np困难的。如果一个2连通图$G$没有2强定向,我们可以问有多少条边可以定向,这样得到的混合图仍然是2强的。类似地,我们可能会问一个2边连通图$G$,我们可以定向多少条边,这样得到的混合图仍然是2弧强的。我们证明了当图满足适当的连通性条件时,这两个问题等价于求出在2边连通图中为了得到4边连通图而必须加倍的最小边数。利用这一点,我们证明这三个问题都是np困难的。最后,我们考虑对有向图$D$的弧$uv$进行定向操作,这意味着用相同顶点之间的无向边替换它。就连通性而言,这相当于将相反的弧$vu$添加到$D$。我们证明了对于每一个$\ell\geq 3$,在一个有向图$D$中,为了得到一个$\ell$ -强有向图$D'$,要找到最小的去向弧数是np困难的。
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