Effectiveness of the scavenging action of NO in vacuum UV photolyses of C2H5Br: 121.6 - 193.1 nm region

Kyung-Hoon Jung, D.K. Oh, K.W. Lee, Y.S. Choi, E. Tschuikow-Roux
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Abstract

The radical scavenging effect of NO, in the system of C2H5Br photolyses in the vacuum UV region, has been studied as a function of the energy content of C2H5 radicals and of the irradiation time.

C2H6, one of the principal reaction products, from the primary radical process in the system can be completely suppressed by adding the appropriate amount of a radical scavenger, e.g. NO at greater than 0.1 Torr. However, by adding an unsuitable amount of NO, e.g. 0.02 Torr of NO and 50 Torr of C2H5Br, the reaction between the C2H5 radical and NO becomes competitive with that of the C2H5 radical and C2H5Br by the following mechanism:

where R represents the C2H5 or C2H4Br radical.

The competitive reaction ratio between the C2H5Br/C2H5 and NO/C2H5 systems was obtained as a function of the irradiation energies with the variation in irradiation time by observing the production of C2H6. The values of kNOI/k1, deduced by comparing the observed and the theoretical values, were found to be 4.0 × 103 at 121.6 nm, 9.5 × 103 at 147 nm, 14.0 × 103 at 163.3 nm, 17.0 × 103 at 174.3 – 174.5 nm and 23.0 × 103 at 193.1 nm.

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真空紫外光解C2H5Br 121.6 ~ 193.1 nm区域NO清除效果的研究
研究了NO在真空紫外区c2hbr光解体系中清除自由基的作用与C2H5自由基能量和辐照时间的关系。C2H6是体系中一次自由基过程的主要反应产物之一,加入适量的自由基清除剂,如NO,在大于0.1 Torr的条件下,可以完全抑制体系中一次自由基过程的生成。然而,如果加入适量的NO,如0.02 Torr的NO和50 Torr的C2H5Br, C2H5自由基与NO的反应就会与C2H5自由基与C2H5Br的反应形成竞争,其机理如下:其中R代表C2H5或C2H4Br自由基。通过观察C2H6的生成,得到了C2H5Br/C2H5体系与NO/C2H5体系的竞争反应比随辐照时间的变化与辐照能量的关系。在121.6 nm处kNOI/k1值为4.0 × 103, 147 nm处为9.5 × 103, 163.3 nm处为14.0 × 103, 174.3 ~ 174.5 nm处为17.0 × 103, 193.1 nm处为23.0 × 103。
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