具有1位输出量化的高斯混合信道的容量实现信号和容量

Md Hasan Rahman, M. Ranjbar, N. Tran, K. Pham
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引用次数: 4

摘要

本文讨论了加性高斯混合(GM)噪声信道使用1位输出量化的最佳信令方案和容量。所考虑的GM分布是具有任意均值的高斯分量密度的加权和,它可以用来表示任何具有工程兴趣的非高斯信道。通过首先建立输入信号最优的充分必要库恩-塔克条件(KTC),我们证明了容量实现信号中质量点的最大数量为4个。我们的证明依赖于Q函数乘积的新界和杜宾定理。考虑具有零平均高斯分量的GM的特殊情况,即异构无线网络中同信道干扰和脉冲干扰的现实精确模型,证明了最优输入为$\pi$/2圆对称。因此,在这种情况下,容量实现信号恰好有四个质量点形成一个以原点为中心的正方形。通过进一步检查改进后的KTC的一阶导数和二阶导数,然后表明,位于第一象限的最佳质量点的相位为$\pi$/4。因此,在GM均值为零的情况下,实现容量的输入信号为QPSK,通道容量可以以封闭形式建立。
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Capacity-Achieving Signal and Capacity of Gaussian Mixture Channels with 1-bit Output Quantization
This paper addresses the optimal signaling scheme and capacity of an additive Gaussian mixture (GM) noise channel using 1-bit output quantization. The considered GM distribution is a weighted sum Gaussian component densities with arbitrary means, and it can be used to represent any non-Gaussian channel of engineering interest. By first establishing a necessary and sufficient Kuhn-Tucker condition (KTC) for an input signal to be optimal, we demonstrate that the maximum number of mass points in the capacity-achieving signal is four. Our proof relies on novel bounds on the product of Q functions and Dubin’s theorem. By considering a special case of GM with zero mean Gaussian components, which is a realistic accurate model for co-channel interference in heterogeneous wireless networks and impulsive interference, it is shown that the optimal input is $\pi$/2 circularly symmetric. As a result, in this case, the capacity-achieving signal has exactly four mass points forming a square centered at the origin. By further checking the first and second derivatives of the modified KTC, it is then shown that the phase of the optimal mass point located in the first quadrant is $\pi$/4. Thus, with zero-mean GM, the capacity-achieving input signal is QPSK, and the channel capacity can be established in closed-form.
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