图分类的积极和无标记学习

Yuchen Zhao, Xiangnan Kong, Philip S. Yu
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引用次数: 43

摘要

近十年来,图的分类问题引起了人们的广泛关注。传统的图分类方法侧重于在监督设置下挖掘判别子图特征。特征选择策略严格遵循正图和负图同时存在的假设。然而,在许多实际应用中,负图示例是不可用的。本文研究了仅基于正图和未标记图选择有用的子图特征并进行图分类的问题。这个问题是具有挑战性的,并且与以前的PU学习工作不同,因为图数据中没有预定义的特征。而且,子图枚举问题是np困难的。我们需要确定一个未标记图的子集,它最有可能是负图。然而,负图选择问题和子图特征选择问题是相互关联的。在解出可靠负图之前,我们需要有一组有用的子图特征。为了解决这个问题,我们首先基于一组估计的负图,推导出一个评估准则来估计子图特征和类标签之间的依赖关系。为了建立基于图数据的PU学习问题的精确模型,我们提出了一种以迭代方式同时选择判别特征和负图的集成方法。实验结果表明了该方法的有效性和高效性。
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Positive and Unlabeled Learning for Graph Classification
The problem of graph classification has drawn much attention in the last decade. Conventional approaches on graph classification focus on mining discriminative sub graph features under supervised settings. The feature selection strategies strictly follow the assumption that both positive and negative graphs exist. However, in many real-world applications, the negative graph examples are not available. In this paper we study the problem of how to select useful sub graph features and perform graph classification based upon only positive and unlabeled graphs. This problem is challenging and different from previous works on PU learning, because there are no predefined features in graph data. Moreover, the sub graph enumeration problem is NP-hard. We need to identify a subset of unlabeled graphs that are most likely to be negative graphs. However, the negative graph selection problem and the sub graph feature selection problem are correlated. Before the reliable negative graphs can be resolved, we need to have a set of useful sub graph features. In order to address this problem, we first derive an evaluation criterion to estimate the dependency between sub graph features and class labels based on a set of estimated negative graphs. In order to build accurate models for the PU learning problem on graph data, we propose an integrated approach to concurrently select the discriminative features and the negative graphs in an iterative manner. Experimental results illustrate the effectiveness and efficiency of the proposed method.
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