数论中的基本方法

S. Scott
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引用次数: 1

摘要

每股3a;- 2x - 5,量子为3a;;每个量子的接收者必须返回+ 2a;加5到资金箱。从资金箱移出6a;磅到A,然后在3a中分布-量子到2a;人,每人返回2x + 5,因此总数为4a;+ 10;如图所示。下一步动作15a;从盒子里拿出来到位置B。在3a外;数量为5个人,每人返回2x + 5,即在C点和25a点共10x;D.下一步行动;依此类推,直至基金减少至45a;-f49和进一步的量子分布是不可能的。商是2a;+ 5;+ 9人,剩余45a人;+ 49磅。
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Elementary methods in the theory of numbers
Each share is 3a; — 2x — 5, the quantum being 3a;; each recipient of a quantum must return + 2a; + 5 to the fund-box. Out of the fund-box move 6a; pounds to A, and there distribute in 3a;-quanta to 2a; persons, who each return 2x + 5 and therefore a total of 4a; + 10a; to the box as shown. Next move 15a; out of the box to position B and there give.out in 3a; quanta to 5x persons who each return 2x + 5, that is, a total of 10x at C and 25a; at D. Next move out 27a; etc. until the fund is reduced to 45a; -f49 and further quantum distribution is impossible. The quotient is 2a; + 5a; + 9 people and the remainder 45a; + 49 pounds.
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