关于环链定理

L. M. Brown
{"title":"关于环链定理","authors":"L. M. Brown","doi":"10.1017/S0950184300000148","DOIUrl":null,"url":null,"abstract":"/ / P l t P2, P3, P* are four points on a circle C, and P234 is the orthocentre of triangle P2 P 3 P4. Piu the orthocentre of triangle P1P3 P4 and so on, then the quadrilateral P234 PISA -P124 -P123 t s congruent to the quadrilateral PlP2PsPi. This theorem seems to be due to Steiner (Oes. Werke, 1, p. 128; see H. F. Baker, Introduction to Plane Geometry, 1943, p. 332) and has appeared frequently since in collections of riders on the elementary circle theorems. It is clear that P234 P134 P124 P123 lie on a circle C1234 equal to the original circle C. But also angle P 3 P134 P4 = P4 Pj P 3 = P4 P2 P 3 = PsP23iPi (with angles directed and equations modulo 77), and hence P 3 P4 P134 P234 lie on a circle C3i equal to C, and which is in fact the mirror image of C in P3P4. Similarly we obtain circles C12, C13, C14, C23, C24, so that we have in all eight circles with four points on each. If any one of these be taken as the original circle, the same system of eight circles is obtained ; if, e.g., we begin with PsPiP^ P234 on the circle C34, the four orthocentres are Pl 5 P2, P123, P m lying on C]2 and the remaining circles are the images of C34 in the six sides of the quadrangle P3 P4 P134 P234. Call this configuration KA. Let us now take a fifth point P5 on C. Then any four of Pj P2 P3 P4 P5 give a Ki. We have in fact five points Pa . . . . P5, ten points P123 . . . . P345, a circle C, ten circles C12 . . . . C45 and five circles C1234 . . . . C2345. Then the circles Cl2U C1235 C12i5 C13ii C2345 all pass through a point Pi2u&, completing a system of 16 poinis and 16 circles, five points on each circle and five circles through each point. We may show this by taking the circle C12, e.g., on which lie the five points P 1 P 2 P ) 2 3 Pi 2 4 Pi 2 5 and build up the K^s obtained by taking these four at a time. Use a parallel notation and write Q1 = Plt Q2 = P2,","PeriodicalId":417997,"journal":{"name":"Edinburgh Mathematical Notes","volume":"5 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1900-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"On a Chain of Circle Theorems\",\"authors\":\"L. M. Brown\",\"doi\":\"10.1017/S0950184300000148\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"/ / P l t P2, P3, P* are four points on a circle C, and P234 is the orthocentre of triangle P2 P 3 P4. Piu the orthocentre of triangle P1P3 P4 and so on, then the quadrilateral P234 PISA -P124 -P123 t s congruent to the quadrilateral PlP2PsPi. This theorem seems to be due to Steiner (Oes. Werke, 1, p. 128; see H. F. Baker, Introduction to Plane Geometry, 1943, p. 332) and has appeared frequently since in collections of riders on the elementary circle theorems. It is clear that P234 P134 P124 P123 lie on a circle C1234 equal to the original circle C. But also angle P 3 P134 P4 = P4 Pj P 3 = P4 P2 P 3 = PsP23iPi (with angles directed and equations modulo 77), and hence P 3 P4 P134 P234 lie on a circle C3i equal to C, and which is in fact the mirror image of C in P3P4. Similarly we obtain circles C12, C13, C14, C23, C24, so that we have in all eight circles with four points on each. If any one of these be taken as the original circle, the same system of eight circles is obtained ; if, e.g., we begin with PsPiP^ P234 on the circle C34, the four orthocentres are Pl 5 P2, P123, P m lying on C]2 and the remaining circles are the images of C34 in the six sides of the quadrangle P3 P4 P134 P234. Call this configuration KA. Let us now take a fifth point P5 on C. Then any four of Pj P2 P3 P4 P5 give a Ki. We have in fact five points Pa . . . . P5, ten points P123 . . . . P345, a circle C, ten circles C12 . . . . C45 and five circles C1234 . . . . C2345. Then the circles Cl2U C1235 C12i5 C13ii C2345 all pass through a point Pi2u&, completing a system of 16 poinis and 16 circles, five points on each circle and five circles through each point. We may show this by taking the circle C12, e.g., on which lie the five points P 1 P 2 P ) 2 3 Pi 2 4 Pi 2 5 and build up the K^s obtained by taking these four at a time. Use a parallel notation and write Q1 = Plt Q2 = P2,\",\"PeriodicalId\":417997,\"journal\":{\"name\":\"Edinburgh Mathematical Notes\",\"volume\":\"5 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"1900-01-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Edinburgh Mathematical Notes\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1017/S0950184300000148\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Edinburgh Mathematical Notes","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1017/S0950184300000148","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0

摘要

/ / p1t P2, P3, P*是圆C上的四个点,P234是三角形P2 p3p4的正心尖。Piu三角形P1P3 P4的正心尖,以此类推,则四边形P234 PISA -P124 -P123 t与四边形PlP2PsPi相等。这个定理似乎是由斯坦纳定理得出的。Werke, 1,第128页;见H. F. Baker,《平面几何导论》,1943年,第332页),此后经常出现在初等圆定理的附注集中。很明显,P234 P134 P124 P123位于与原圆C相等的圆C1234上,但角p3p134 P4 = P4 Pj p3 = P4 P2 p3 = PsP23iPi(角有向,方程模为77),因此P3P4 P134 P234位于等于C的圆C3i上,这实际上是P3P4中C的镜像。同样地,我们得到了圆C12, C13, C14, C23, C24,所以我们有八个圆,每个圆上有四个点。如果取其中任何一个圆作为原始圆,则得到相同的八个圆系统;例如,我们从圆C34上的PsPiP^ P234开始,四个正心是位于C]2上的Pl 5 P2, P123, pm,其余的圆是C34在四边形P3 P4 P134 P234的六个边的像。将此配置称为KA。现在我们在c上取第五个点P5,那么任意四个pjp2 P3 p4p5就得到一个Ki。我们实际上有5个点Pa . . . .P5, 10分P123 . . . .P345,一个圆圈C,十个圆圈C12 . . . .C45和五个圆C1234 . . . .C2345。然后圆圈Cl2U C1235 C12i5 C13ii C2345都经过一个点Pi2u&,完成一个16点16圆的系统,每个圆上有5个点,每个点上有5个圆。我们可以通过取圆C12来证明这一点,例如,在圆C12上有5个点p1 p2 p2 2 3 2 4 2 5然后通过一次取这4个点来建立K^s。用平行符号写Q1 = Plt Q2 = P2,
本文章由计算机程序翻译,如有差异,请以英文原文为准。
查看原文
分享 分享
微信好友 朋友圈 QQ好友 复制链接
本刊更多论文
On a Chain of Circle Theorems
/ / P l t P2, P3, P* are four points on a circle C, and P234 is the orthocentre of triangle P2 P 3 P4. Piu the orthocentre of triangle P1P3 P4 and so on, then the quadrilateral P234 PISA -P124 -P123 t s congruent to the quadrilateral PlP2PsPi. This theorem seems to be due to Steiner (Oes. Werke, 1, p. 128; see H. F. Baker, Introduction to Plane Geometry, 1943, p. 332) and has appeared frequently since in collections of riders on the elementary circle theorems. It is clear that P234 P134 P124 P123 lie on a circle C1234 equal to the original circle C. But also angle P 3 P134 P4 = P4 Pj P 3 = P4 P2 P 3 = PsP23iPi (with angles directed and equations modulo 77), and hence P 3 P4 P134 P234 lie on a circle C3i equal to C, and which is in fact the mirror image of C in P3P4. Similarly we obtain circles C12, C13, C14, C23, C24, so that we have in all eight circles with four points on each. If any one of these be taken as the original circle, the same system of eight circles is obtained ; if, e.g., we begin with PsPiP^ P234 on the circle C34, the four orthocentres are Pl 5 P2, P123, P m lying on C]2 and the remaining circles are the images of C34 in the six sides of the quadrangle P3 P4 P134 P234. Call this configuration KA. Let us now take a fifth point P5 on C. Then any four of Pj P2 P3 P4 P5 give a Ki. We have in fact five points Pa . . . . P5, ten points P123 . . . . P345, a circle C, ten circles C12 . . . . C45 and five circles C1234 . . . . C2345. Then the circles Cl2U C1235 C12i5 C13ii C2345 all pass through a point Pi2u&, completing a system of 16 poinis and 16 circles, five points on each circle and five circles through each point. We may show this by taking the circle C12, e.g., on which lie the five points P 1 P 2 P ) 2 3 Pi 2 4 Pi 2 5 and build up the K^s obtained by taking these four at a time. Use a parallel notation and write Q1 = Plt Q2 = P2,
求助全文
通过发布文献求助,成功后即可免费获取论文全文。 去求助
来源期刊
自引率
0.00%
发文量
0
期刊最新文献
Latent Roots of Tri-Diagonal Matrices The Existence of Integrals of Dynamical Systems Linear in the Velocities A New Look for Hamiltonian Dynamics Inertia Invariants of a Set of Particles Linkages for the Trisection of an Angle and Duplication of the Cube
×
引用
GB/T 7714-2015
复制
MLA
复制
APA
复制
导出至
BibTeX EndNote RefMan NoteFirst NoteExpress
×
×
提示
您的信息不完整,为了账户安全,请先补充。
现在去补充
×
提示
您因"违规操作"
具体请查看互助需知
我知道了
×
提示
现在去查看 取消
×
提示
确定
0
微信
客服QQ
Book学术公众号 扫码关注我们
反馈
×
意见反馈
请填写您的意见或建议
请填写您的手机或邮箱
已复制链接
已复制链接
快去分享给好友吧!
我知道了
×
扫码分享
扫码分享
Book学术官方微信
Book学术文献互助
Book学术文献互助群
群 号:481959085
Book学术
文献互助 智能选刊 最新文献 互助须知 联系我们:info@booksci.cn
Book学术提供免费学术资源搜索服务,方便国内外学者检索中英文文献。致力于提供最便捷和优质的服务体验。
Copyright © 2023 Book学术 All rights reserved.
ghs 京公网安备 11010802042870号 京ICP备2023020795号-1