{"title":"正级数的不等式","authors":"C. Walsh","doi":"10.1017/S0950184300002706","DOIUrl":null,"url":null,"abstract":"Let f(x) ≡ (1 – x) b + b a b-1 x o (x) ≡ x c – c Β c-1 x where b ≧ 1, c ≧ 1, 0 ≦ α ≦ 1, 0 ≦ β ≦ 1, and x is assumed to lie in the range (0, 1). By differentiation, or otherwise, it is easily shewn that f(x) and o ( x ) have minima when x = 1 – α and when x = β , respectively. Hence (1 – x) b + a b-1 x ≧ b a b-1 + (1 – b) a b x c β c-1 x ≧ (1 – c)β c .","PeriodicalId":417997,"journal":{"name":"Edinburgh Mathematical Notes","volume":"32 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1900-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"1","resultStr":"{\"title\":\"Inequalities for Positive Series\",\"authors\":\"C. Walsh\",\"doi\":\"10.1017/S0950184300002706\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"Let f(x) ≡ (1 – x) b + b a b-1 x o (x) ≡ x c – c Β c-1 x where b ≧ 1, c ≧ 1, 0 ≦ α ≦ 1, 0 ≦ β ≦ 1, and x is assumed to lie in the range (0, 1). By differentiation, or otherwise, it is easily shewn that f(x) and o ( x ) have minima when x = 1 – α and when x = β , respectively. Hence (1 – x) b + a b-1 x ≧ b a b-1 + (1 – b) a b x c β c-1 x ≧ (1 – c)β c .\",\"PeriodicalId\":417997,\"journal\":{\"name\":\"Edinburgh Mathematical Notes\",\"volume\":\"32 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"1900-01-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"1\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Edinburgh Mathematical Notes\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1017/S0950184300002706\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Edinburgh Mathematical Notes","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1017/S0950184300002706","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 1
摘要
让f (x)≡(1 - x) b + b b - 1 x o (x)≡x c - cΒ颈- 1 b≧1 x, c≧1,0≦α≦1 0≦β≦1,假设和x躺在(0,1)范围。通过分化,或否则,它很容易尚能f (x)和o (x)最小值时x = 1 -α和x =β,分别。因此(1 - x) b + a -1 x≧b a -1 + (1 - b) a b x c β c-1 x≧(1 - c)β c。
Let f(x) ≡ (1 – x) b + b a b-1 x o (x) ≡ x c – c Β c-1 x where b ≧ 1, c ≧ 1, 0 ≦ α ≦ 1, 0 ≦ β ≦ 1, and x is assumed to lie in the range (0, 1). By differentiation, or otherwise, it is easily shewn that f(x) and o ( x ) have minima when x = 1 – α and when x = β , respectively. Hence (1 – x) b + a b-1 x ≧ b a b-1 + (1 – b) a b x c β c-1 x ≧ (1 – c)β c .