欧氏算法:

S. Mneimneh
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引用次数: 0

摘要

考虑两个正整数a0 > a1。a0和a1的最大公约数,记作gcd(a0, a1)是最大的正整数g,使得g|a0和g|a1,即g能整除a0和a1。观察1:gcd(a0, a1)始终存在。观察2(欧euclid):设a0 = q1a1 + r,其中0≤r < a1(注意这个表示总是可能且唯一的),则gcd(a0, a1) = gcd(a1, r)。这个事实的证明包括表明d|a0和d|a1⇔d|a1和d|r。
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The Euclidean Algorithm:
1 The greatest common divisor Consider two positive integers a0 > a1. The greatest common divisor of a0 and a1, denoted gcd(a0, a1) is the largest positive integer g such that g|a0 and g|a1, i.e. g divides both a0 and a1. Observation 1: The gcd(a0, a1) always exists. Observation 2 (Euclid): Let a0 = q1a1 + r where 0 ≤ r < a1 (note that this representation is always possible and unique), then gcd(a0, a1) = gcd(a1, r). The proof of this fact consists of showing that d|a0 and d|a1 ⇔ d|a1 and d|r.
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