罗密欧与朱丽叶的问题:最小化视线距离

Hee-Kap Ahn, Eunjin Oh, Lena Schlipf, Fabian Stehn, Darren Strash
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引用次数: 2

摘要

我们引入了守望者路线问题的一个变体,我们称之为最快对可见性问题。假设有两个人站在没有孔的简单多边形P$ s$和$t$处,我们想要最小化他们移动的距离以便在P$中看到彼此。我们解决了这个问题的两个变体,一个是在线性时间内最优地最小化两人旅行的较长距离(min-max),另一个是最小化总旅行距离(min-sum)。对于最小-最大变量,我们还考虑了这个问题的查询版本。我们可以在线性时间内预处理一个简单的$n$-gon,这样对于任意两个查询位置$s, $ t,我们可以在$O(\log^2 n)$时间内计算出两个人旅行的最远距离的最小值。
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On Romeo and Juliet Problems: Minimizing Distance-to-Sight
We introduce a variant of the watchman route problem, which we call the quickest pair-visibility problem. Given two persons standing at points $s$ and $t$ in a simple polygon $P$ with no holes, we want to minimize the distance they travel in order to see each other in $P$. We solve two variants of this problem, one minimizing the longer distance the two persons travel (min-max) and one minimizing the total travel distance (min-sum), optimally in linear time. We also consider a query version of this problem for the min-max variant. We can preprocess a simple $n$-gon in linear time so that the minimum of the longer distance the two persons travel can be computed in $O(\log^2 n)$ time for any two query positions $s,t$ where the two persons start.
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