从移动应用程序使用模式中识别任务

Yuan Tian, K. Zhou, M. Lalmas, D. Pelleg
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引用次数: 13

摘要

移动设备已经成为我们日常生活中越来越普遍的一部分。我们使用移动服务来执行广泛的任务(例如预订旅行或办公室工作),导致不同应用程序和服务之间的交互通常很长。现有的移动系统主要处理简单的用户需求,其中单个应用程序被视为交互单元。为了理解用户的期望并提供上下文感知的服务,在任务空间中对用户的交互建模是很重要的。在这项工作中,我们首先提出并评估了一种将用户应用程序使用日志自动分割为任务单元的方法。我们关注两个问题:(i)给定一对连续的应用程序使用日志,确定是否存在任务边界;(ii)给定任意一对两个应用程序使用日志,确定它们是否属于同一任务。我们将这些问题建模为使用应用使用模式三个方面特征的分类问题:时间、相似性和日志序列。我们的分类器改进了传统的超时分割,在这两个问题上都实现了89%以上的性能。其次,我们在商业移动应用程序使用日志的大规模数据集上使用我们最好的任务分类器来识别常见任务。我们观察到,用户执行了从定期信息查看到娱乐和预订晚餐等常见任务。我们提出的任务识别方法提供了评估与任务完成相关的移动服务和应用程序的方法。
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Identifying Tasks from Mobile App Usage Patterns
Mobile devices have become an increasingly ubiquitous part of our everyday life. We use mobile services to perform a broad range of tasks (e.g. booking travel or office work), leading to often lengthy interactions within distinct apps and services. Existing mobile systems handle mostly simple user needs, where a single app is taken as the unit of interaction. To understand users' expectations and to provide context-aware services, it is important to model users' interactions in the task space. In this work, we first propose and evaluate a method for the automated segmentation of users' app usage logs into task units. We focus on two problems: (i) given a sequential pair of app usage logs, identify if there exists a task boundary, and (ii) given any pair of two app usage logs, identify if they belong to the same task. We model these as classification problems that use features from three aspects of app usage patterns: temporal, similarity, and log sequence. Our classifiers improve on traditional timeout segmentation, achieving over 89% performance for both problems. Secondly, we use our best task classifier on a large-scale data set of commercial mobile app usage logs to identify common tasks. We observe that users' performed common tasks ranging from regular information checking to entertainment and booking dinner. Our proposed task identification approach provides the means to evaluate mobile services and applications with respect to task completion.
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