论从具有与非扭曲斯坦伯格代数不同构的扭曲斯坦伯格代数的丰满豪斯多夫群集构造群集

Rizalyn Bongcawel, Lyster Rey Cabardo, Gaudencio C. Petalcorin, Jr., Jocelyn Vilela
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引用次数: 0

摘要

本研究介绍了一个广义豪斯多夫类群 $\hat{A}\rtimes\mathcal{R}$;从一个充裕的 Hausdorff 类群 $\mathcal{G}$ 和一个单元交换环 $R$ 中抽取出来的 Hausdorff 类群 $D$,它是在 $\hat{A} 上的离散捻转。\rtimes \mathcal{R}$上的离散扭转。从类群 C*-algebra 的角度来看,当 $R = \mathbb{C}$ 时,非扭曲类群 C*-algebra $(C^*(\mathcal{G}))$ 与扭曲类群 C*-algebra $(C^*(\hat{A} \rtimes\mathcal{R};D))$ 之间是同构的。然而,在本文中,从纯代数的角度来看,非扭曲的斯坦伯格代数 $(A_R(\mathcal{G}))$ 和扭曲的斯坦伯格代数 $(A_R(D; \hat{A} \rtimes \mathcal{R}))$ 是非同构的。
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On the Construction of a Groupoid from an Ample Hausdorff Groupoid with Twisted Steinberg Algebra not Isomorphic to its Non-twisted Steinberg Algebra
This study introduces an ample Hausdorff groupoid $\hat{A} \rtimes \mathcal{R}$ extracted from an ample Hausdorff groupoid $\mathcal{G}$ and a unital commutative ring $R$; a Hausdorff groupoid $D$ which is the discrete twist over $\hat{A} \rtimes \mathcal{R}$. In the groupoid C*-algebra perspective, when $R = \mathbb{C}$ there is an isomorphism between the non-twisted groupoid C*-algebra $(C^*(\mathcal{G}))$ and the twisted groupoid C*-algebra $(C^*(\hat{A} \rtimes \mathcal{R};D))$. However, in this paper, in a purely algebraic setting, the non-twisted Steinberg algebra $(A_R(\mathcal{G}))$ and the twisted Steinberg algebra $(A_R(D; \hat{A} \rtimes \mathcal{R}))$ are non-isomorphic.
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CiteScore
1.30
自引率
28.60%
发文量
156
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