有界关系长度的基群和群呈现

Pub Date : 2024-05-10 DOI:10.1007/s10711-024-00915-1
Sergio Zamora
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引用次数: 0

摘要

我们研究了具有微不足道的第一贝蒂数(first Betti number)的紧凑测地空间的几何,这些空间容纳了大量有限的等距群。我们证明,如果一个有限群 G 通过等向作用于第一贝蒂数消失的紧凑大地空间 X,那么 \({\text {diam}}(X) / {\text {diam}}(X / G ) \le 4 \sqrt{ \vert G \vert }\).对于一个群 G 和一个有限对称生成集 S,\(P_k(\varGamma (G, S))\) 表示二维 CW 复数,其 1 骨架是 G 关于 S 的 Cayley 图\(\varGamma \),其 2 单元是 m-gons,为 \(0 \le m \le k\)、中长度为 m 的简单图环所定义,直至循环排列。让 G 是一个有限无边群,具有 \(\vert G \vert \ge 3\) ,S 是一个对称的子集,其中 \(P_k(\varGamma (G,S))\) 具有微不足道的第一个贝蒂数。我们证明了 Cayley 图上的拉普拉奇的第一个非难特征值 \(-\lambda _1\) 满足 \(\lambda _1 \ge 2 - 2 \cos ( 2 \pi / k ) \)。我们还给出了 G 的 Cayley 图关于 S 的直径的显式上界,其形式为 \(O (k^2 \vert S \vert \log \vert G \vert )\)。还得到了一对 (G, S) 的切格常数和卡兹丹常数的相关显式边界。
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Fundamental groups and group presentations with bounded relator lengths

We study the geometry of compact geodesic spaces with trivial first Betti number admitting large finite groups of isometries. We show that if a finite group G acts by isometries on a compact geodesic space X whose first Betti number vanishes, then \({\text {diam}}(X) / {\text {diam}}(X / G ) \le 4 \sqrt{ \vert G \vert }\). For a group G and a finite symmetric generating set S, \(P_k(\varGamma (G, S))\) denotes the 2-dimensional CW-complex whose 1-skeleton is the Cayley graph \(\varGamma \) of G with respect to S and whose 2-cells are m-gons for \(0 \le m \le k\), defined by the simple graph loops of length m in \(\varGamma \), up to cyclic permutations. Let G be a finite abelian group with \(\vert G \vert \ge 3\) and S a symmetric set of generators for which \(P_k(\varGamma (G,S))\) has trivial first Betti number. We show that the first nontrivial eigenvalue \(-\lambda _1\) of the Laplacian on the Cayley graph satisfies \(\lambda _1 \ge 2 - 2 \cos ( 2 \pi / k ) \). We also give an explicit upper bound on the diameter of the Cayley graph of G with respect to S of the form \(O (k^2 \vert S \vert \log \vert G \vert )\). Related explicit bounds for the Cheeger constant and Kazhdan constant of the pair (GS) are also obtained.

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