{"title":"空间直线与圆阶相交图的复杂性","authors":"Jean Cardinal","doi":"arxiv-2406.17504","DOIUrl":null,"url":null,"abstract":"We consider the complexity of the recognition problem for two families of\ncombinatorial structures. A graph $G=(V,E)$ is said to be an intersection graph\nof lines in space if every $v\\in V$ can be mapped to a straight line $\\ell (v)$\nin $\\mathbb{R}^3$ so that $vw$ is an edge in $E$ if and only if $\\ell(v)$ and\n$\\ell(w)$ intersect. A partially ordered set $(X,\\prec)$ is said to be a circle\norder, or a 2-space-time order, if every $x\\in X$ can be mapped to a closed\ncircular disk $C(x)$ so that $y\\prec x$ if and only if $C(y)$ is contained in\n$C(x)$. We prove that the recognition problems for intersection graphs of lines\nand circle orders are both $\\exists\\mathbb{R}$-complete, hence polynomial-time\nequivalent to deciding whether a system of polynomial equalities and\ninequalities has a solution over the reals. The second result addresses an open\nproblem posed by Brightwell and Luczak.","PeriodicalId":501216,"journal":{"name":"arXiv - CS - Discrete Mathematics","volume":"19 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-06-25","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"The Complexity of Intersection Graphs of Lines in Space and Circle Orders\",\"authors\":\"Jean Cardinal\",\"doi\":\"arxiv-2406.17504\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"We consider the complexity of the recognition problem for two families of\\ncombinatorial structures. A graph $G=(V,E)$ is said to be an intersection graph\\nof lines in space if every $v\\\\in V$ can be mapped to a straight line $\\\\ell (v)$\\nin $\\\\mathbb{R}^3$ so that $vw$ is an edge in $E$ if and only if $\\\\ell(v)$ and\\n$\\\\ell(w)$ intersect. A partially ordered set $(X,\\\\prec)$ is said to be a circle\\norder, or a 2-space-time order, if every $x\\\\in X$ can be mapped to a closed\\ncircular disk $C(x)$ so that $y\\\\prec x$ if and only if $C(y)$ is contained in\\n$C(x)$. We prove that the recognition problems for intersection graphs of lines\\nand circle orders are both $\\\\exists\\\\mathbb{R}$-complete, hence polynomial-time\\nequivalent to deciding whether a system of polynomial equalities and\\ninequalities has a solution over the reals. The second result addresses an open\\nproblem posed by Brightwell and Luczak.\",\"PeriodicalId\":501216,\"journal\":{\"name\":\"arXiv - CS - Discrete Mathematics\",\"volume\":\"19 1\",\"pages\":\"\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2024-06-25\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"arXiv - CS - Discrete Mathematics\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/arxiv-2406.17504\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - CS - Discrete Mathematics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2406.17504","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
The Complexity of Intersection Graphs of Lines in Space and Circle Orders
We consider the complexity of the recognition problem for two families of
combinatorial structures. A graph $G=(V,E)$ is said to be an intersection graph
of lines in space if every $v\in V$ can be mapped to a straight line $\ell (v)$
in $\mathbb{R}^3$ so that $vw$ is an edge in $E$ if and only if $\ell(v)$ and
$\ell(w)$ intersect. A partially ordered set $(X,\prec)$ is said to be a circle
order, or a 2-space-time order, if every $x\in X$ can be mapped to a closed
circular disk $C(x)$ so that $y\prec x$ if and only if $C(y)$ is contained in
$C(x)$. We prove that the recognition problems for intersection graphs of lines
and circle orders are both $\exists\mathbb{R}$-complete, hence polynomial-time
equivalent to deciding whether a system of polynomial equalities and
inequalities has a solution over the reals. The second result addresses an open
problem posed by Brightwell and Luczak.