{"title":"关于\"$e^π$和$π^{e}$哪个更大?经典难题的非正统物理解决方案\"","authors":"Roderick M. Macrae","doi":"arxiv-2407.09568","DOIUrl":null,"url":null,"abstract":"In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and\nBove provide a physical argument based nominally on the second law of\nthermodynamics as a way of resolving the mathematical question appearing in the\ntitle. A remarkable aspect of their argument is that it does not depend on the\nnumerical value of $\\pi$, because $e^{x} \\ge x^{e}$ for all positive $x$, with\nequality occurring only when $x = e$. Moreover, their argument does not depend\non the validity of the second law but is rather a limited proof of it for this\nparticular case.","PeriodicalId":501482,"journal":{"name":"arXiv - PHYS - Classical Physics","volume":"32 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-07-08","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Comment on \\\"Which is greater: $e^π$ or $π^{e}$? An unorthodox physical solution to a classic puzzle\\\"\",\"authors\":\"Roderick M. Macrae\",\"doi\":\"arxiv-2407.09568\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and\\nBove provide a physical argument based nominally on the second law of\\nthermodynamics as a way of resolving the mathematical question appearing in the\\ntitle. A remarkable aspect of their argument is that it does not depend on the\\nnumerical value of $\\\\pi$, because $e^{x} \\\\ge x^{e}$ for all positive $x$, with\\nequality occurring only when $x = e$. Moreover, their argument does not depend\\non the validity of the second law but is rather a limited proof of it for this\\nparticular case.\",\"PeriodicalId\":501482,\"journal\":{\"name\":\"arXiv - PHYS - Classical Physics\",\"volume\":\"32 1\",\"pages\":\"\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2024-07-08\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"arXiv - PHYS - Classical Physics\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/arxiv-2407.09568\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - PHYS - Classical Physics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2407.09568","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
Comment on "Which is greater: $e^π$ or $π^{e}$? An unorthodox physical solution to a classic puzzle"
In a recent Note (Am. J. Phys. 92:397, 2024; arXiv:2309.10826), Vallejo and
Bove provide a physical argument based nominally on the second law of
thermodynamics as a way of resolving the mathematical question appearing in the
title. A remarkable aspect of their argument is that it does not depend on the
numerical value of $\pi$, because $e^{x} \ge x^{e}$ for all positive $x$, with
equality occurring only when $x = e$. Moreover, their argument does not depend
on the validity of the second law but is rather a limited proof of it for this
particular case.