与椭圆函数有关的一类函数的凸性和凹性

Mohamed Bouali
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摘要

我们研究了函数$$f_a(x)=\frac{{\cal K}{(\sqrt x)}}{a-(1/2)\log(1-x)} 在$(0,1)$上的凸性。$$ 我们证明,当且仅当 $a\geq a_c$ 时,$f_a$ 在 $(0,1)$ 上是严格凸的,当且仅当 $a\leq\log 4$ 时,$1/f_a$ 在 $(0,1)$ 上是严格凸的,其中 $a_c$ 是某个临界值。本文的第二个主要结果是研究函数 $$h_p(x)=(1-x)^p{cal K}(\sqrt x) 的对数凸性和对数凹性。我们证明,当且仅当 $p\geq 7/32$ 时,$h_p$ 在 $(0,1)$ 上是严格对数凹的,当且仅当 $p\leq 0$ 时,$h_p$ 是严格对数凸的。这就解决了杨和田提出的一些问题,并完成了他们的结果和阿尔泽和理查德的结果:当且仅当$a=4/3$时,$f_a$在$(0,1)$上是严格凹的,当且仅当$a\geq 8/5$时,$1/f_a$在$(0,1)$上是严格凹的。作为凸性和凹性的应用,我们建立了这样的不等式:对于 $a\geqa_c$ 和所有 $r\in(0、1)$$$frac{2pi\sqrt\pi}{(2a+\log 2)\Gamma(3/4)^2}\leq\frac{cal K}(\sqrt r)}{a-\frac12\log (r)}+\frac{calK}(\sqrt{1-r})}{a-\frac12\log (1-r)}<1+\frac\pi{2a}、$$ 并且对于 $p\geq 3(2+\sqrt2)/8$ 和所有 $r\in(0、1)$$$sqrt{(r-r^2)^p{cal K}(\sqrt{1-r}){cal K}(\sqrtr)}<\frac{pi\sqrt\pi}{2^{p+1}\Gamma(3/4)^2}<\frac{r^p{calK}(\sqrt{1-r})+(1-r)^p{cal K}(\sqrt r)}{2}。$$
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Convexity and concavity of a class of functions related to the elliptic functions
We investigate the convexity property on $(0,1)$ of the function $$f_a(x)=\frac{{\cal K}{(\sqrt x)}}{a-(1/2)\log(1-x)}.$$ We show that $f_a$ is strictly convex on $(0,1)$ if and only if $a\geq a_c$ and $1/f_a$ is strictly convex on $(0,1)$ if and only if $a\leq\log 4$, where $a_c$ is some critical value. The second main result of the paper is to study the log-convexity and log-concavity of the function $$h_p(x)=(1-x)^p{\cal K}(\sqrt x).$$ We prove that $h_p$ is strictly log-concave on $(0,1)$ if and only if $p\geq 7/32$ and strictly log-convex if and only if $p\leq 0$. This solves some problems posed by Yang and Tian and complete their result and a result of Alzer and Richards that $f_a$ is strictly concave on $(0,1)$ if and only if $a=4/3$ and $1/f_a$ is strictly concave on $(0,1)$ if and only if $a\geq 8/5$. As applications of the convexity and concavity, we establish among other inequalities, that for $a\geq a_c$ and all $r\in(0,1)$ $$\frac{2\pi\sqrt\pi}{(2a+\log 2)\Gamma(3/4)^2}\leq \frac{{\cal K}(\sqrt r)}{a-\frac12\log (r)}+\frac{{\cal K}(\sqrt{1-r})}{a-\frac12\log (1-r)}<1+\frac\pi{2a},$$ and for $p\geq 3(2+\sqrt 2)/8$ and all $r\in(0,1)$ $$\sqrt{(r-r^2)^p{\cal K}(\sqrt{1-r}){\cal K}(\sqrt r)}< \frac{\pi\sqrt\pi}{2^{p+1}\Gamma(3/4)^2}<\frac{r^p{\cal K}(\sqrt{1-r})+(1-r)^p{\cal K}(\sqrt r)}{2}.$$
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