无穷多周变数有理函数域的吕洛特定理

M. Rovinsky
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引用次数: 0

摘要

L\"uroth 定理描述了有理曲线在一个域上的支配映射。在这篇论文中,我们研究了在一个域$k$上的绝对不可还原变种$X$的笛卡尔幂$X^{/Psi}$的主映射,这些笛卡尔幂$X^{/Psi}$的无限集$\Psi$相对于因子$X$的所有排列是等变的。至少有一些这样的映射是以组合$h:X^{\Psi}\xrightarrow{f^{\Psi}}Y^{\Psi}}\to H\backslash Y^{\Psi}$的形式出现的,其中$X\xrightarrow{f}Y$是一个占优的$k$映射,而$H$是$Y|k$的一个自变群$H$,对角地作用于$Y^{\Psi}$。在特征为 0 的情况下,如果 $\dim X=1$ ,我们将证明这种构造经过适当修改后,可以给出来自 $X^{Psi}$ 的所有主导等变映射。对于任意的 $X$,结果只是部分的。在以后的论文中,我们将研究这种 $h$'s 目标上的 "类相干 "等变剪切。一些初步结果已经出现在 arXiv:math/2205.15144 中。一个有点类似的问题是检查 $X^{Psi}$的不可还原无变量子域是否作为 $Y^{Psi}$(对于适当的 $f$'s)对角嵌入 $Y^{Psi}$ 的子域的 $f^{Psi}$ 下的回拉而出现。这将是对科恩(D.E.Cohen)关于对称ideal的noetherian性质的著名定理的补充。我们证明,如果 $\dim X=1$ 时,情况就是这样。
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Lüroth's theorem for fields of rational functions in infinitely many permuted variables
L\"uroth's theorem describes the dominant maps from rational curves over a field. In this note we study the dominant maps from cartesian powers $X^{\Psi}$ of absolutely irreducible varieties $X$ over a field $k$ for infinite sets $\Psi$ that are equivariant with respect to all permutations of the factors $X$. At least some of such maps arise as compositions $h:X^{\Psi}\xrightarrow{f^{\Psi}}Y^{\Psi}\to H\backslash Y^{\Psi}$, where $X\xrightarrow{f}Y$ is a dominant $k$-map and $H$ is an automorphism group $H$ of $Y|k$, acting diagonally on $Y^{\Psi}$. In characteristic 0, we show that this construction, when properly modified, gives all dominant equivariant maps from $X^{\Psi}$, if $\dim X=1$. For arbitrary $X$, the results are only partial. In a subsequent paper, the `quasicoherent' equivariant sheaves on the targets of such $h$'s will be studied. Some preliminary results have already appeared in arXiv:math/2205.15144. A somewhat similar problem is to check, whether the irreducible invariant subvarieties of $X^{\Psi}$ arise as pullbacks under $f^{\Psi}$ (for appropriate $f$'s) of subvarieties of $Y$ diagonally embedded into $Y^{\Psi}$. This would be a complement to the famous theorem of D.E.Cohen on the noetherian property of the symmetric ideals. We show that this is the case if $\dim X=1$.
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