论 Max-2Lin(2) 的 NP-Hardness 近似曲线

Björn Martinsson
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引用次数: 0

摘要

在 \maxtlint{} 问题中,你会得到一个形式为$x_i + x_j \equiv b \pmod{2}$的方程组,你的目标是找到一个能满足尽可能多方程的赋值。让 $c \in [0.5, 1]$ 表示可满足方程的最大分数。在本文中,我们将构建一条曲线 $s (c)$,这样就可以 \NPhard{} 找到至少满足 $s$ 等式的解。这条曲线符合或改进了所有之前已知的 \maxtlint{} 的不可逼近性 NP-hardness结果。特别是,我们证明了如果 $c \geqslant 0.9232$,那么 $frac{1 - s (c)}{1 - c}> 1.48969$,这改进了删除版 \maxtlint{} 的 NP-困难不可逼近常数。我们的工作是对奥唐纳和吴的工作的补充,后者在假设唯一游戏猜想的前提下研究了同一问题。与之前针对 \maxtlint{} 的不可逼近性结果类似,我们使用了来自 $(2^k - 1)$ary Hadamard ㄊ的小工具还原。之前的工作使用的 $k$ 范围从 $2$ 到 $4$。我们的主要成果是一个程序,用于获取某个固定 $k$ 的小工具,当 $k$ 趋于无穷大时,以它为基石构建出越来越好的小工具。我们的方法既可以用来提高手工创建的小工具的结果 $(k = 3)$,也可以用来提高用计算机构建的大工具的结果 $(k=4)$。
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On the NP-Hardness Approximation Curve for Max-2Lin(2)
In the \maxtlint{} problem you are given a system of equations on the form $x_i + x_j \equiv b \pmod{2}$, and your objective is to find an assignment that satisfies as many equations as possible. Let $c \in [0.5, 1]$ denote the maximum fraction of satisfiable equations. In this paper we construct a curve $s (c)$ such that it is \NPhard{} to find a solution satisfying at least a fraction $s$ of equations. This curve either matches or improves all of the previously known inapproximability NP-hardness results for \maxtlint{}. In particular, we show that if $c \geqslant 0.9232$ then $\frac{1 - s (c)}{1 - c} > 1.48969$, which improves the NP-hardness inapproximability constant for the min deletion version of \maxtlint{}. Our work complements the work of O'Donnell and Wu that studied the same question assuming the Unique Games Conjecture. Similar to earlier inapproximability results for \maxtlint{}, we use a gadget reduction from the $(2^k - 1)$-ary Hadamard predicate. Previous works used $k$ ranging from $2$ to $4$. Our main result is a procedure for taking a gadget for some fixed $k$, and use it as a building block to construct better and better gadgets as $k$ tends to infinity. Our method can be used to boost the result of both smaller gadgets created by hand $(k = 3)$ or larger gadgets constructed using a computer $(k = 4)$.
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