最大化 MST 比率的复杂性

Afrouz Jabal Ameli, Faezeh Motiei, Morteza Saghafian
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引用次数: 0

摘要

给定 $\mathbb{R}^d$ 中红色和蓝色点的有限集合,MST-ratio 是红色点的欧氏最小生成树和蓝色点的欧氏最小生成树的总长度除以它们的联盟的欧氏最小生成树的长度。一个点集的最大 MST 比率是该点集所有非三色着色的红点和蓝点的最大 MST 比率。我们证明,当维度是输入的一部分时,求给定点集的最大 MST 比率问题是 NP 难的。此外,我们还提出了一种运行时间为 O(n^2)$ $3$ 的近似计算法。作为证明的一部分,我们证明了在任何度量空间中,最大 MST 比率都小于$3$。此外,我们还研究了一组 $n$ 点的所有着色的平均 MST 比率。我们证明,这个平均值总是至少 $\frac{n-2}{n-1}$,而且对于均匀分布在 $d$ 维单位立方体中的 $n$ 随机点,当 $n$ 变为无穷大时,平均值在期望值上趋于 $\sqrt[d]{2}$。
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The Complexity of Maximizing the MST-ratio
Given a finite set of red and blue points in $\mathbb{R}^d$, the MST-ratio is the combined length of the Euclidean minimum spanning trees of red points and of blue points divided by the length of the Euclidean minimum spanning tree of the union of them. The maximum MST-ratio of a point set is the maximum MST-ratio over all non-trivial colorings of its points by red and blue. We prove that the problem of finding the maximum MST-ratio of a given point set is NP-hard when the dimension is a part of the input. Moreover, we present a $O(n^2)$ running time $3$-approximation algorithm for it. As a part of the proof, we show that in any metric space, the maximum MST-ratio is smaller than $3$. Additionally, we study the average MST-ratio over all colorings of a set of $n$ points. We show that this average is always at least $\frac{n-2}{n-1}$, and for $n$ random points uniformly distributed in a $d$-dimensional unit cube, the average tends to $\sqrt[d]{2}$ in expectation as $n$ goes to infinity.
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